Answer:
Q = 1252.82kJ
Explanation:
Mass = 179g
Initial temperature (T1) = 25°C = (25+273.15)K = 298.15K
Final temperature (T2) = 82.70°C = (82.70 + 273.15)K = 335.85K
Specific heat capacity (c) = 121.3J/g.K
Heat energy (Q) = mc∇T
M = mass of the substance
Q = heat energy
c = specific heat capacity of the substance
∇T = change in temperature of the substance = T2 - T1
Q = mc∇T
Q = 179 × 121.3 × (355.85 - 298.15)
Q = 21712.7 × 57.7
Q = 1,252,822.79
Q = 1252.82kJ
The heat energy required to heat 179g of acetic acid from 25°C to 82.70°C is 1252.82kJ
Answer:
<u>1</u>Al₄C₃ + <u>12</u>H₂O → <u>3</u>CH₄ + <u>4</u>Al(OH)₃
Explanation:
<u>SOLUTION :-</u>
Balance it by using 'hit & trial' method , and you'll get the answer :-
<u>1</u>Al₄C₃ + <u>12</u>H₂O → <u>3</u>CH₄ + <u>4</u>Al(OH)₃
<u>VERIFICATION :-</u>
<em>In reactant side of equation :-</em>
- Number of atoms in Al = 1×4 = 4
- Number of atoms in C = 1×3 = 3
- Number of atoms in H = 12×2 = 24
- Number of atoms in O = 12×1 = 12
<em>In product side of equation :-</em>
- Number of atoms in C = 3×1 = 3
- Number of atoms in H = (3×4) + 4(1×3) = 24
- Number of atoms in Al = 4×1 = 4
- Number of atoms in O = 4(1×3) = 12
Number of atoms of each element is equal in both reactant & product side of equation. Hence , the equation is balanced.
<span>The reason why it is easiest to assume the first step is slow is because that would be your rate determining step and would give you the rate law given in the problem. So you take the two compounds from the rate law given and put them as your two reactants in your first step:
NO2 + F2 ---> NO2F + F (all gases)
Your next step needs to make sense for your overall reaction. And you also need to have an intermediate which in this case will be F:
F + NO2 ---> NO2F (again all gases) This is the fast step.
Your intermediate cancels out to give you your overall equation:
2NO2 + F2 ---> 2NO2F (all gases)</span>
Answer:
In cellular respiration, complex molecules containing carbon react with oxygen to produce carbon dioxide and other materials. ... Matter is conserved during cellular respiration because atoms are conserved in physical and chemical processes
Explanation:
I hope this helps
There are three kinds of Hydrogen in 2-methyl-2-butene
The correct question is
How many kinds of hydrogen atoms are present in 2-methyl-2-butene
<h3>What is an atom ?</h3>
Atom was discovered by Dalton's Atomic theory , he predicted that each element consist of large number of a very small thing known as atom.
In the structure of 2-methyl-2-butene there are 3 types oh Hydrogen
1. Attached to the Carbon atom connecting the methyl ion to the butene
2. Connected to the last Carbon atom
3. Connected to the Carbon bond having double bond.
Therefore there are three kinds of Hydrogen in 2-methyl-2-butene.
To know more about Atom
brainly.com/question/1566330
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