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LekaFEV [45]
3 years ago
12

Two genes on chromosome 7 of corn are identified by the recessive alleles gl (glossy), which determines glossy leaves, and ra (r

amosa), which determines branching of ears. When a plant heterozygous for each of these alleles was crossed with a homozygous recessive plant, the progeny consisted of the following genotypes:
Gl ra 88 gl Ra 103
Gl Ra 6 gl ra 3
a. What is the frequency of recombination between these genes?
Biology
1 answer:
Alchen [17]3 years ago
3 0

Answer:

recombination frequency = 4.5% or 4.5mu

Explanation:

to calculate the frequency of recombination between these genes

we have,

recombination frequency = [ number of recombinnants/total number of offsprings) x 100

total offspring  = 88 + 103 + 6 + 3

total offspring =  200

Gl ra 88............................ parent

gl Ra 103.........................parent

Gl Ra 6..................................... recombinant

gl ra 3................................................ recombinant

recombination frequency = {6+3/88 + 103 + 6 + 3} x 100

recombination frequency = 9/200 x1oo

recombination frequency = 0.045 x 100

recombination frequency = 4.5% or 4.5mu

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joja [24]

Answer:

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7 0
3 years ago
To learn how different organisms might be related, scientists look for similarities and differences between the organisms. On th
tensa zangetsu [6.8K]

Answer:

To learn how different organisms might be related, scientists look for similarities and differences between the organisms. On the lines below, compare a cat and a frog. What physical features are the same? What physical features are different?

Cat and Frog are both vertebrates as they possess backbone.

Cat belongs to the family fenidae while frog belongs to the family bufonidae and their classes are mammals and amphibia respectively

Explanation:

7 0
3 years ago
Which of the following is an example of natural selection?
Alexxx [7]

Answer:

A) Hummingbirds drinking nectar from a plant.

Step-by-step explanation:

Here are some examples of natural selection: In a habitat there are red bugs and green bugs. The birds prefer the taste of the red bugs, so soon there are many green bugs and few red bugs. The green bugs reproduce and make more green bugs and eventually there are no more red bugs.

8 0
3 years ago
Read 2 more answers
If a blue eyed mother with a normal vision has a brown eyed color blind son and a blue eyed colored blind daughter what are the
Rina8888 [55]

Answer: mother: XX^aa, father: X^YAa, son: X^YAa, daughter: X^X^aa.

Explanation:

Color blindness is a genetic disorder that affects the ability to distinguish colors. It is hereditary and is transmitted by an X-linked recessive allele. If a male inherits an X chromosome with the altered allele he will be color blind. In contrast, females, who have two X chromosomes, will only be colorblind if both of their X chromosomes have the altered allele. This is because <u>males have one X chromosome and one Y chromosome, while females have two X chromosomes</u>.  

If the woman has normal vision, that means she cannot have both chromosomes affected. She can only have one affected chromosome (be a carrier) or none at all. Also, if she has blue eyes, which is a recessive trait, then both alleles are recessive. But the eye color is not on the X chromosome. For example, her eye color genotype can only be aa, because if she had at least one dominant allele she would have brown eye color. As for the other trait, she can be XX^, with X^ being an affected (carrier) allele or XX, i.e. both normal. So in summary, her genotype can be XXaa or XX^aa  

If she has a brown-eyed male child who is also colour blind, he has inherited the allele for colour blindness from his mother, since the father does not pass on an X chromosome to the male children, only the Y. With this we can now rule out the mother's XXaa genotype since she had to have passed on her affected X^ chromosome. Then the genotype of the mother is XX^aa. And since her mother can only pass on one allele to (recessive) because she does not have allele A, the dominant that determines her brown eye color can only come from the father. So the genotype of this son is X^YAa. The female daughter has color blindness and blue eyes. So she had to inherit the affected X^ chromosome from the mother (which we already know she has) and an affected X^ chromosome from the father, because the daughter needs to inherit both affected X^ chromosomes to develop the disease. And if she also has blue eyes, she had to have inherited a recessive allele from the mother and another from the father. So with this information we can say that the father's genotype can only be X^YAa. Because the father must have both A and A alleles of the same eye color, because he passed the dominant one to the son and the recessive one to the daughter. At last, the genotype of the daughter is X^X^aa.

8 0
4 years ago
The following is an excerpt from the case study "It's All Greek to Me": "I am sorry to give you bad news. Nikoleta does have ane
Sholpan [36]
<span>This treatment would have failed because although she has anemia, it doesn't mean that she is low in iron. Giving her treatment with iron could possible give her more than she needs in her body. The true cause of Nikoleta's anemia was that her beta proteins in the hemoglobin are not working properly. This was probably discovered through family history if the family had that type of anemia, since the condition could be inherited, or it was found through blood tests.</span>
6 0
4 years ago
Read 2 more answers
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