Momentum = mass x acceleration
5 x 2 = 10 kg. m/s
Answer:
A. 52 min
.A. 47 watts
Explanation:
Given that;
jim weighs 75 kg
and he walks 3.3 mph; the objective here is to determine how long must he walk to expend 300 kcal.
Using the following relation to determine the amount of calories burned per minute while walking; we have:

here;
MET = energy cost of a physical activity for a period of time
Obtaining the data for walking with a speed of 3.3 mph From the standard chart for MET, At 3.3 mph; we have our desired value to be 4.3
However;
the calories burned in a minute = 
= 5.644
Therefore, for walking for 52 mins; Jim burns approximately 293.475 kcal which is nearest to 300 kcal.
4.
Given that:
mass m = 75 kg
intensity = 6 kcal/min
The eg ergometer work rate = ??
Applying the formula:

where ;



∴
Converting to watts;
Since; 6.118kg-m/min is = 1 watt
Then 291.66 kgm /min will be equal to 47.67 watts
≅ 47 watts
Answer:
the focal length is 4cm
Explanation:
use the formula 1+1/m = f
it is obtained from the mirror formula
m is the magnification and is the ratio of the image height to the object height
however they should have the same unit . that means you would have to do a little conversion from cm to mm or vice versa .
Answer:
A d-t graph's slope is equivalent to the speed and direction while a v-t graph's slope is equal to its acceleration. A constant slope for a d-t graph means that the speed is constant. The area underneath a v-t graph would be its distance.
Explanation:
In fission, an atom is split into two or more smaller, lighter atoms. Fusion, in contrast, occurs when two or more smaller atoms fuse together, creating a larger, heavier atom. For the former, the energy released by fission is a million times greater than that released in chemical reactions, but lower than the energy released by nuclear fusion. On the other hand, fusion process<span> is three to four times greater than the energy released by fission. Hope this would help. Have a nice day.</span>