Answer:
Elastically
Explanation:
A rock that has deformed Elastically under stress keeps its new shape when the stress is released.
In elastic deformation the original shape of the object is regained when the stress is removed. Whereas in plastic deformation the original shape is parmanently deformed with the application of stress.
A.) kiloliter. 1 kiloliter = 1,000 liters
c.) megaliter. 1 megaliter = 1,000,000 liters
hope this helps
Answer:
Amplitude = 8 Volts
Frequency = 0.067 kHz
Explanation:
Note: The missing picture in question is attached for your review.
Given:
Volts/Div = 2 V/div
Time/Div = 5 msec/div
Finding Amplitude:
Now, as you can see in the attached picture, there are 4 division between two peaks of the waveform, so,
![Amplitude = 4 div/volts * 2 volts/ div )\\Amplitude = 8 Volts](https://tex.z-dn.net/?f=Amplitude%20%3D%204%20div%2Fvolts%20%2A%202%20volts%2F%20div%20%29%5C%5CAmplitude%20%3D%208%20Volts)
(Multiplying by 2 V/div because oscilloscope dial is set at 2 V/div)
Finding Frequency:
As can be seen in attached picture, 3 division are there for one complete cycle of waveform,so,
![Time Period = 3 div * 5msec /div\\Time Perod = 15 msec](https://tex.z-dn.net/?f=Time%20Period%20%3D%203%20div%20%2A%205msec%20%2Fdiv%5C%5CTime%20Perod%20%3D%2015%20msec)
Since,
![Frequency = \frac{1}{Time Period}\\Frequency = \frac{1}{15m}\\Frequency = 0.067 kHz](https://tex.z-dn.net/?f=Frequency%20%3D%20%5Cfrac%7B1%7D%7BTime%20Period%7D%5C%5CFrequency%20%3D%20%5Cfrac%7B1%7D%7B15m%7D%5C%5CFrequency%20%3D%200.067%20kHz)
Answer:
∆T = Mv^2Y/2Cp
Explanation:
Formula for Kinetic energy of the vessel = 1/2mv^2
Increase in internal energy Δu = nCVΔT
where n is the number of moles of the gas in vessel.
When the vessel is to stop suddenly, its kinetic energy will be used to increase the temperature of the gas
We say
1/2mv^2 = ∆u
1/2mv^2 = nCv∆T
Since n = m/M
1/2mv^2 = mCv∆T/M
Making ∆T subject of the formula we have
∆T = Mv^2/2Cv
Multiple the RHS by Cp/Cp
∆T = Mv^2/2Cv *Cp/Cp
Since Y = Cp/CV
∆T = Mv^2Y/2Cp k
Since CV = R/Y - 1
We could also have
∆T = Mv^2(Y - 1)/2R k
That is true Step by step: