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olganol [36]
3 years ago
7

Can somebody help please ! a. -8.3 m/s b.-4.2 m/s c.-0.12 m/s d. 0 m/s

Physics
1 answer:
Gnom [1K]3 years ago
4 0
The answer is a
the \: answer \: is \: a.
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A flat uniform circular disk (radius = 2.30 m, mass = 1.00 ✕ 102 kg) is initially stationary. The disk is free to rotate in the
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The resulting angular speed = 0.6 rad / s.

<u>Explanation:</u>

Here there is no external torque acting on the system thus we can apply the law of conservation of angular  momentum  

Angular momentum of the man = Iω

Where I = Inertia of the man about the axis of rotation

or         I = M r 2

            I  = 50 * 1.25*1.25 = 78.125

w = Angular velocity of the man, that can be calculated as follows

Tangential velocity of man = v = 2m/s  

So time taken to describe this circle is t = (2*pi* r) / v

Now angle described in 1 revolution θ = 2*pi radians

This angle is subtended in time t = (2*pi* r) / v

Thus angular speed = w = θ/t = 2*pi* ( v/ 2π r) = v/r = 2.70 / 1.25 = 2.16 rad/s

So angular momentum of man = Iw = 78.125 * 2.16 = 168.75.

To conserve the angular momentum before and after,

Angular momentum of disk = angular momentum of the man  

           i.e.             Iw of disk = 168.75

                                disk of I = (disk of M*R^2) / 2

                                              = (1.00 * 102 * 2.30 * 2.30) / 2

                                              = 269.79

                 Thus 269.79 of disk of w = 168.75

      Resulting angular speed of disk = 168.75 / 269.79 = 0.6 ras / s

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3 years ago
When light is reflected, the incident rays are bent and change direction.<br> True<br> False
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Answer: True

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Two blocks a and b ($m_a&gt;m_b$) are pushed for a certain distance along a frictionless surface. how does the magnitude of the
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Explanation:

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