Write two expressions that have a GCF of 8xy

irinina [24]

Answer: 70.909090909091%

Step-by-step explanation: Reading through the problem we have 78 is, that's 78 equals, what percent, x/100, of 110, times 110.

It's important to understand that percent means over 100 so what percent would simply mean x/100 or any variable but I will be using x.

So we have the equation $78 = \frac{x}{100} *110$

So cross canceling the 110 and 100 to 11 and 10, we have $78 = \frac{11x}{10}$

Multiply both sides by 10 to get rid

of the fraction and we have 780 = 11x.

Now divide both sides by 11 and 70.909090909091 = x.

So, 78 is 70.909090909091% of 110.

Work is attached in the image provided.

8 0

3 years ago

Does anyone know this? its for a test , please ?!

konstantin123 [22]

Answer:

11) Irrational number

12) Integer

13) Communitive property of addition

14) Distributive property of addition and multipacation

15) 26

16) 8

17) -41

18) 65

19) -5x-20

Step-by-step explanation:

Hope I helped

4 0

3 years ago

Find the ordered pair that makes both the equations below true

NNADVOKAT [17]

Answer:

(3, 1)

Step-by-step explanation:

(a) Algebraic solution

(1) y = -⅔x + 3

(2) y = 2x - 5

Set Equation (1) equal to Equation (2)

-⅔x + 3 = 2x - 5

Multiply each side by 3

-2x + 9 = 6x - 15

Add 15 to each side

-2x + 24 = 6x

Add 2x to each side

24 = 8x

Divide each side by 3

(3) x = 3

Substitute (3) into (2)

y = 2×3 - 5 = 6 - 5 = 1

The ordered pair that makes both equations true is (3, 1).

(b) Graphical solution

In the diagram below, the red line is the graph of Equation (1). The blue line is the graph of Equation (2). The point of intersection is at (3, 1).

7 0

3 years ago

A group of 54 college students from a certain liberal arts college were randomly sampled and asked about the number of alcoholic

Ket [755]

Answer:

$t=\frac{5.25-4.73}{\frac{3.98}{\sqrt{54}}}=0.9601$

P-value

First we find the degrees of freedom given by:

$df = n-1= 54-1=53$

Since is a two-sided test the p value would be:

$p_v =2*P(t_{53}>0.9601)=0.3414$

Step-by-step explanation:

Data given and notation

$\bar X=5.25$ represent the sample mean

$s=3.98$ represent the sample standard deviation

$n=54$ sample size

$\mu_o =4.73$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean differs from 4.73, the system of hypothesis would be:

Null hypothesis: $\mu =4.73$

Alternative hypothesis: $\mu \neq 4.73$

Since we know don't the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{5.25-4.73}{\frac{3.98}{\sqrt{54}}}=0.9601$

P-value

First we find the degrees of freedom given by:

$df = n-1= 54-1=53$

Since is a two-sided test the p value would be:

$p_v =2*P(t_{53}>0.9601)=0.3414$

7 0

3 years ago

In the figure AB||CD and EIA is congruent to GJB

Rzqust [24]

The answers
1) D. (TRANSITIVE PROPERTY OF CONGRUENCY)
2) C. (LINEAR PAIR THEOREM)
3) D. TRANSITIVE PROPERTY OF CONGRUENCY) to equations (1) and (2), we get m∠IKL + m∠JLD = 180°.
4) C. (CONGRUENT SUPPLEMENTS THEOREM)

8 0

3 years ago

Read 2 more answers