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Grace [21]
3 years ago
13

Write two expressions that have a GCF of 8xy

Mathematics
1 answer:
-BARSIC- [3]3 years ago
3 0
32x^2y
8xy^6
the gcf is 8xy
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Find the degree measures of the next two positive and the previous two negative angles that are coterminal with the angle 75°.
AlladinOne [14]

9514 1404 393

Answer:

  • 435°, 795°
  • -285°, -645°

Step-by-step explanation:

Add or subtract multiples of 360° to find coterminal angles.

<u>Positive</u>

  75° +360° = 435°

  75° +2×360° = 795°

<u>Negative</u>

  75° -360° = -285°

  75° -2×360° = -645°

5 0
3 years ago
please help please help please please please please please please please please please please please please please please please
7nadin3 [17]
Answer:
1) -10^3 (-10 to the power of 3)
2) r^5 (pie to the power of 5)
3) 1/2^2 + x^3 (1/2 to the power of 2 + x to the power of 3)
3 0
3 years ago
What graph is a function of x
Nookie1986 [14]
Show me the picture for I can help u
3 0
3 years ago
How do you do this question?
Ksivusya [100]

Answer:

V = (About) 22.2, Graph = First graph/Graph in the attachment

Step-by-step explanation:

Remember that in all these cases, we have a specified method to use, the washer method, disk method, and the cylindrical shell method. Keep in mind that the washer and disk method are one in the same, but I feel that the disk method is better as it avoids splitting the integral into two, and rewriting the curves. Here we will go with the disk method.

\mathrm{V\:=\:\pi \int _a^b\left(r\right)^2dy\:},\\\mathrm{V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy}

The plus 1 in '1 + 2/x' is shifting this graph up from where it is rotating, but the negative 1 is subtracting the area between the y-axis and the shaded region, so that when it's flipped around, it becomes a washer.

V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy,\\\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=\pi \cdot \int _1^3\left(1+\frac{2}{y}\right)^2-1dy\\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\= \pi \left(\int _1^3\left(1+\frac{2}{y}\right)^2dy-\int _1^31dy\right)\\\\

\int _1^3\left(1+\frac{2}{y}\right)^2dy=4\ln \left(3\right)+\frac{14}{3}, \int _1^31dy=2\\\\=> \pi \left(4\ln \left(3\right)+\frac{14}{3}-2\right)\\=> \pi \left(4\ln \left(3\right)+\frac{8}{3}\right)

Our exact solution will be V = π(4In(3) + 8/3). In decimal form it will be about 22.2 however. Try both solution if you like, but it would be better to use 22.2. Your graph will just be a plot under the curve y = 2/x, the first graph.

5 0
3 years ago
How many solutions can a single variable linear equation contain?
dimaraw [331]
No solution is  the correct answer i  think
6 0
3 years ago
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