Answer:
The expected number of calls in one hour is 30.
The probability of three calls in five minutes is 
The probability of no calls in a five-minutes is 
Step-by-step explanation:
We know that the calls come in at the rate of one every two minutes. To find the expected number of calls in one hour you need to:

To find the probability of these events:
- three calls in five minutes
- no calls in a five-minutes
We are going to use the Poisson distribution because is used when it is desirable to determine the probability of obtaining x occurrences over an interval of time like in this situation.
The Poisson probability function is defined by

where
x = 0, 1, 2, 3 ...
e = 2.71828
μ = mean number of successes in the given time interval or region of space
- To find the probability of three calls in five minutes you need to:
Find μ

Evaluate the formula for k = 3 and μ = 2.5

- To find the probability of no calls in a five-minute period you need to:
Evaluate the formula for k = 0 and μ = 2.5

Answer: 0
<u>Step-by-step explanation:</u>
g(x) = x² + 6x ; x ≥ -3
To find the inverse, swap the x's and y's and solve for "y":
x = y² + 6y
x + 9 = y² + 6y + 9 <em>add 9 to both sides to create a perfect square</em>
x + 9 = (y + 3)²
= y + 3 <em>take square root of both sides</em>
= y ; y ≥ -3
g⁻¹(0) = 
= 
= -3 ± 3
= -3 + 3 , -3 - 3
= 0 , -6
since the restriction is: y ≥ -3, then -6 is not valid
Answer:
2,375 joules I think............
Answer:
3/4*46,777777(de) drop the 4 and you get 1/5
Step-by-step explanation:
"Per" means "divided by", so "cost per ounce" means "cost"/"ounces".
The difference in cost per ounce is
.. (1.14/12) -(1.28/16) = .095 -.08 = 0.015
Brand X costs 1.5¢ more per ounce than Brand Y.