Answer:
The answer is 6 if you need an explanation I have one
Twelve people join hands for a circle dance.In how many ways can they do this? Suppose six of these people are men, and the other six are women. In how many ways can they join hands for a circle dance, assuming they alternate in gender around the circle
Answer:
86400 ways
Step-by-step explanation:
Since the circle can be rotated, the number of ways to arrange a distinct number of n objects in a circle will be (n−1)!.
Now, if we rotate the circle with the six women, we will see that there are 5! ways with which they can be placed in the circle.
After picking the places for the women, we will now fill each gap between two women with a man.
We have 6 men. Thus, number of ways to arrange the men is 6!
Thus,number of ways they can join hands for a circle dance, assuming they alternate in gender around the circle = 5! × 6! = 86400 ways
What question I didn't get it
∠G would be congruent to ∠J
∠B would be congruent to ∠K
∠P would be congruent to ∠Y
Hope this helps :)
Answer:
The answer would be function 2.
Step-by-step explanation:
I found this out by plugging in 0 into x. What I got then was one. So I found that function 2 has a spot on 0, 1. that is how I got the answer.
Brainliest would be appreciated.
