Answer:
Peter Jonathan Winston (March 18, 1958 – disappeared January 26, 1978) was an American chess player from New York City
Step-by-step explanation:
In late 1977, Winston attended a FIDE-rated tournament at Hunter College High School in New York City. Despite being one of the highest-rated players in the tournament, Winston lost all nine of his games. A few months later, on January 26, 1978, following further surprising game losses, Peter Winston vanished and was never heard from again. According to some sources, Winston's disappearance occurred when he left his home without money, identification, or luggage during a severe winter storm. Many chess players who were close to or acquainted with Winston claim that the champion chess player's mental health had deteriorated, along with his game performance, in the last few years of his life, and that the decline in his mental health may have led to his disappearance.
John is 31 and Jenny is 26
Answer:
Step-by-step explanation:
The equation of a straight line can be represented in the slope-intercept form, y = mx + c
Where
m = slope
c = intercept
The equation of the given line is
y = 47x - 3
Comparing with the slope intercept equation, m = 47
If two lines are parallel, it means that they have equal slope. This means that the slope of the line passing through (14, 4) is 47
We would determine the intercept, c by substituting m= 47, x = 14 and y = 4 into y = mx + c. It becomes
4 = 47× 14 + c
4 = 658 + c
c = 4 - 658 = - 654
The equation becomes
y = 47x - 654
Answer:
7*7*7
Step-by-step explanation:
Answer:
test statistic is ≈ -0.36
p-value is ≈ 0.64
There is no significant evidence that the average golfer can hit the ball more than 235 yards on average.
Step-by-step explanation:
a hypothesis test where H_0: mu = 235 and H_1:mu > 235
test statistic can be calculated as follows:
z=
where
- sample mean driving distance (233.8 yards)
- M is the average expected distance that the average golfer can hit the ball under null hypothesis. (235 yards)
- s is the standard deviation (46.6 yards)
- N is the sample size (192)
Then test statistic is z=
=-0.3568
p-value is 0.64 >0.05
There is no significant evidence that the average golfer can hit the ball more than 235 yards on average.
