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frez [133]
3 years ago
8

Which unit would you use to measure the amount of water used to water a lawn?

Mathematics
1 answer:
marysya [2.9K]3 years ago
8 0
You would use mL
mm and g are not used for liquid and L is too big
You might be interested in
Which of the following is equivalent to | − 12 + 3 | ?
melisa1 [442]

Answer:

9

Step-by-step explanation:

The answer to | − 12 + 3 | is 9 because if you add -12 + 3, you get -9. However, since it is the <em>absolute value</em>, we would make it the same number but positive.

Hope this helped! :)

5 0
3 years ago
Read 2 more answers
The sum of interior angles in a triangle are 180 degrees. Angle B and C are congruent. Angle B is twenty less than angle A. Writ
Margarita [4]

Answer:

A = 73.33

B = 53.33

C = 53.33

Step-by-step explanation:

Mathematically, adding the 3 angles would equal 180

Thus;

A + B + C = 180 •••••(i)

Since B and C are congruent, that means they are equal ( we are looking at isosceles triangle)

B = C •••••••••(ii)

Lastly;

B = A -20 ••••••••(iii)

Make a substitution in equation 1;

A + A -20 + A -20 = 180

Since B = C ; C also is A-20

3A -40 = 180

3A = 220

A = 220/3 = 73.33

B = C = A -20 = 73.33 -20 = 53.33

6 0
3 years ago
How do you find the area of this
devlian [24]

Answer:

156 cm^2

Step-by-step explanation:

area of a paralelogram is Base times hieght

13 times 12

4 0
3 years ago
Which if the following items showed the greatest percentage in bulk
Katyanochek1 [597]
No image shown but just remember that percentage is out of 100

0.03 is 3%
7 0
3 years ago
Suppose xy=−4 and dy/dt=−3. Find dx/dt when x=−1.
user100 [1]
When x=-1: \quad (-1)y=-4\qquad\to\qquad y=4\)

Ok that gives us a little more information.
If we implicitly differentiate with respect to t, from the very start, then we can apply our product rule, ya?

x'y+xy'=0

The right side is zero, derivative of a constant is zero.
Where x' is dx/dt and y' is dy/dt.

From here, plug in all the stuff you know:
y' = -3
x = -1
y = 4

and solve for x'.

Hope that helps!
4 0
3 years ago
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