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2 years ago

Which unit would you use to measure the amount of water used to water a lawn?

Mathematics

1 answer:

marysya [2.9K]2 years ago

8 0

You would use mL
mm and g are not used for liquid and L is too big

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What is the value of y? Enter your answer in the box. y =

Olenka [21]

Answer:

$y=40\°$

Step-by-step explanation:

we know that

An isosceles triangle has two equal sides and two equal angles

The two equal angles are called the base angles and the third angle is called the vertex angle

In this problem the triangle ABC is an isosceles triangle

$AB=AC$

$5x=40\°$

$x=8\°$

The sum of the internal angles of a triangle is equal to $180\°$

Find the value of y

$(2y+20)\°+2(40\°)=180\°$

$2y=180\°-20\°-80\°$

$2y=80\°$

$y=40\°$

6 0

3 years ago

Read 2 more answers

15c² - 5c. Factorise completely

KATRIN_1 [288]

Looking at the problem, what we must do to complete this question is to completely factor the expression that was provided. The expression that was provided is $15c^2 - 5c$ .

The first step that we must do is to take a look at the expression and see what the two pieces of the expression have in common. We can see that both $15c^2$ and $-5c$ have the number 5 and the variable c associated with them so we can factor out those two.

Factor out 5c

$15c^2 - 5c$

$5c(\frac{15c^2}{5c}) - 5c(\frac{5c}{5c})$

$5c(3c) - 5c(1)$

$5c(3c - 1)$

Now we have completely factored out the expression that was provided in the problem statement and we came to final answer of $5c(3c - 1)$ .

7 0

1 year ago

Read 2 more answers

Simplify: Cube root of (128a^13b^6)

Pavlova-9 [17]

$\sqrt[3]{128a^{13}b^{6}} \\\sqrt[3]{64a^{12}b^{6} * 2a} \\\sqrt[3]{64a^{12}b^{6}}\sqrt[3]{2a} \\4a^{4}b^{2}\sqrt[3]{2a}$

7 0

3 years ago

Natali [406]

The ratio of the area of ∆ABC to the area of ∆DEF is; 1:100.

<h3>What is the ratio of the area of ∆ABC to the area of ∆DEF?</h3>

Since, a major criterion for similarity and congruence of triangles is that the ratio of corresponding sides are equal.

On this note, since the task content suggest that the ratio of the perimeters is; 1:10, it follows from conventional mathematics that the ratio of their areas is given as; 1²:10²; 1:100.