Answer:
I'm doing the same thing lol I'm 12
<span>To do these you will be adding or subtracting 2pi (or integer multiples of .
Since the given angles are in fraction form, it will help to have 2pi in fraction form, 2pi=10/5=6pi/3=4pi/2=18pi/9 NOTE: this>(/) stands for over like 1 over 2 EX. 1/2
too, so the addition/subtraction is easier.
Hint: When deciding if you have a number between 0 and 2pi, compare it to the fraction version of 2pi that you've been adding/subtracting.
For 17pi/5...
First we can see that 17pi/5 is more than 10pi/5 (aka 2pi). So we need to start subtracting: 17pi/5 - 10pi/5 = 7pi/5
Now we have a number between 0 and 10pi/5. So 7pi/5 is the co-terminal angle between 0 and 2pi.
I'll leave the others for you to do. Just remember that you might have to add or subtract multiple times before you get a number between 0 and 2pi.
P.S don't add or subtract at all if the number starts out between 0 and 2pi.</span>
Answer:
60 cents
Step-by-step explanation:
First you have to make them to a common denominator.
5/6 7/12 7/10
50/60 35/60 42/60
from these the greatest value is 35/60 because 35 parts of 60 is bigger than the rest.
so the answer is 7/12
Answer:
Part 1) The exponential function is equal to 
Part 2) The population in 2010 was
Step-by-step explanation:
Part 1) Write an exponential decay function that models this situation
we know that
In this problem we have a exponential function of the form

where
y ----> the fish population of Lake Collins since 2004
x ----> the time in years
a is the initial value
b is the base
we have


substitute
----> exponential function that represent this scenario
Part 2) Find the population in 2010
we have
so
For 
substitute