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3 years ago

Help with 30 please I forget what supplementary and complementary mean

Mathematics

1 answer:

NARA [144]3 years ago

6 0

Answer:

a. ∠AMB, ∠BMC

b. ∠BMC, ∠CMD

Step-by-step explanation:

supplementary=angles add up to 180°

Complementary=angles add up to 90°

You might be interested in

Calculate the area of the regular pentagon below: A regular pentagon with side length of 11.8 inches and dotted line from center

vlada-n [284]

Answer:

Area of regular pentagon is 238.95 square inches.

Step-by-step explanation:

Given a regular pentagon with side length of 11.8 inches and dotted line from center to middle of side of 8.1 inches.

we know a regular polygon divides into 5 congruent triangles.

Side of pentagon i.e base of one triangle is 11.8 inches.

Also, distance from center to middle of side which is height of triangle is 8.1 inches.

Area of 1 triangle= $\frac{1}{2}\times base\times height$

= $\frac{1}{2}\times 11.8\times 8.1$

= 47.79 sq inches.

Area of regular pentagon=area of 5 congruent triangles= $5\times 47.79$ =238.95 sq inches.

5 0

3 years ago

You have a new mobile phone. the phone costs £140 and then you pay for a one year contract at £15 a month. how much do you pay i

wel

£140 + £15(month) =

£140 + £15(12) =

£140 + £180 =

£320

3 0

3 years ago

Dividing a power of 4 by 4 is equivalent to (dividing, increasing, reducing, multiplying) the exponent by (10, 2, 1, 4).

Lina20 [59]

Answer:

Dividing a power of 4 by 4 is equivalent to ( reducing,) the exponent by (1).

Step-by-step explanation:

Let the power of 4 be 3

4 *4*4

We divide by 4

4*4*4/4 = 4*4 = 4^2

So we removed 1 power

Notice that 3-1 =2

Let 4 be raised to any power

4^a

We divide by 4

4^a/4 we remove 1 of the powers

we are left with

4^(a-1)

So we reduce the exponent by 1

4 0

3 years ago

Read 2 more answers

1. Write a quadratic function, in standard form, that fits the set of points. Solve it as a system of three equations

sasho [114]

Answer:

The equation is $y=2x^2+4x-7$

Step-by-step explanation:

Let the quadratic function be

$y=ax^2+bx+c$

The point (-4,9) must satisfy this function,

$\Rightarrow a(-4)^2+b(-4)+c=9$

$\Rightarrow 16a-4b+c=9...(1)$

The point (0,-7) must also satisfy this function,

$\Rightarrow a(0)^2+b(0)+c=-7$

$\Rightarrow c=-7...(2)$

The point (1,-1) must also satisfy this function,

$\Rightarrow a(1)^2+b(1)+c=-1$

$\Rightarrow a+b+c=-1...(3)$

We put equation 2 into equation 1 to get;

$\Rightarrow 16a-4b-7=9$

$\Rightarrow 16a-4b=16$

$\Rightarrow 4a-b=4...(5)$

We again put equation 2 into equation 3 to get;

$\Rightarrow a+b-7=-1$

$\Rightarrow a+b=6...(6)$

We add equation 5 and 6 to get;

$5a=10$

$\Rightarrow a=2$

We put $a=2$ into equation 6 to get;

$2+b=6$

$\Rightarrow b=6-2$

$\Rightarrow b=4$

The equation is therefore $y=2x^2+4x-7$

5 0

3 years ago

12x-9y=36 X-intercept is Y- intercept is

n200080 [17]

Answer:

x-int is 3

y-int is -4

Step-by-step explanation:

when x is zero, -9y = 36

y = -4

when y = zero 12x = 36

x = 3

7 0

3 years ago