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zhannawk [14.2K]
3 years ago
7

Need help pleasethxs​

Mathematics
1 answer:
GenaCL600 [577]3 years ago
4 0
The result should be 4 if it’s using PEMDAS
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These box plots show daily low temperatures for a sample of days in two
Elan Coil [88]

Answer:

The answer is B.

Step-by-step explanation:

As you can see, box plot A is symmetrical so that applies to answers A and B. However, box B is very skewed to the right which makes it positively skewed so answer B is the only one that matches the correct description of the two box and whisker plots.

8 0
3 years ago
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The system shown is _____.<br><br> equivalent<br> independent<br> inconsistent
Setler [38]

By definition:

  • If a system has at least one solution, it's said to be consistent.
  • If a system has exactly one solution, it's independent.
  • If a system has infinite solutions, it's dependent
  • If a system has no solutions, it's inconsistent.

Your system has exactly one solution (the two lines represent the two equations, and the point where they meet is the solution of the system), and so it is consistent, and in particular independent.

6 0
4 years ago
What is 1+1. 100 points to whoever gets it first. Answer fast!
Anni [7]

Answer:

da answer iz two cause wen u add one plus one u get answer two

Step-by-step explanation:

let mi hope dat it useful

4 0
3 years ago
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By what number must 566 be divided so as to give a quotient 15 and a remainder 11? (with steps)​
olchik [2.2K]

Answer:

37

Step-by-step explanation:

we would had to call the number needed a random value or call it x but

let's do the calculation backward to ease things up

(566 - 11) ÷15 ➡ 555 ÷ 15 = 37

6 0
4 years ago
PLEASE HELP
Virty [35]

<u>Answer-</u>

\boxed{\boxed{\dfrac{\widehat{BC}}{\widehat{DE}}=\dfrac{3}{4}}}

<u>Solution-</u>

We know that arc length is the product of radius and central angle in radian.

i.e \text{Arc length}=\text{Radius}\times \text{Central angle}

Here,

\theta_{BC}=1.18\ rad,\ \theta_{DE}=2.36\ rad\\\\AD=\dfrac{2}{3}AB\Rightarrow AB=\dfrac{3}{2}AD

So,

\dfrac{\widehat{BC}}{\widehat{DE}}=\dfrac{AB\times 1.18}{AD\times 2.36}

=\dfrac{\frac{3}{2}AD\times 1.18}{AD\times 2.36}

=\dfrac{3\times 1}{2\times 2}

=\dfrac{3}{4}

4 0
3 years ago
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