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Artemon [7]
3 years ago
7

-1/2÷ _____ = -7/3. what is the missing number

Mathematics
1 answer:
satela [25.4K]3 years ago
7 0
3/14 i think.................
You might be interested in
Mhanifa u helped me with this question.... U said it was 25 and its not so why is it wrong
Yanka [14]

Hey I don't know who Mhanifa is but 25 is correct, and I will put the entire explanation to how to get the answer here.

First of all the 2 lines on the left and right side of the triangles are means that those 2 lines are equal and thus forming a isosceles triangle.

This means that the bottom right angle is also 2x+2 degrees.

Now because all 3 angles in a triangle adds to 180 degrees, we can set up equation.

3x+1+2x+2+2x+2=180

Now combine like terms

7x+5=180

Then solve, first subtract 5 from both sides.

7x=175

Now divide 7 from both sides

x=25

6 0
3 years ago
Read 2 more answers
How do I find the measurements of this triangle
Rudik [331]
Using sine law: 

9/sinc = 15/sin22 

sinc = 9sin22 / 15 = 0.225 

so c = sin^-1(0.225) = 12.99 degrees ~~ 13 degrees

if B was required:

B = 180  - C - A ~~  145 

8 0
3 years ago
I really need help with this problem asap? I would be so grateful if you could help!!!
g100num [7]
Assuming that you got the numbers right and that I did my calculations right, then the answer is <span>2998.45 tons.</span>
5 0
3 years ago
Please help me with this question
san4es73 [151]

Step-by-step explanation:

Given: f'(x) = x^2e^{2x^3} and f(0) = 0

We can solve for f(x) by writing

\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx

Let u = 2x^3

\:\:\:\:du=6x^2dx

Then

\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du

\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k

We know that f(0) = 0 so we can find the value for k:

f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}

Therefore,

\displaystyle f(x) = \frac{1}{6} \left(e^{2x^3} - 1 \right)

5 0
3 years ago
In the solution to this system, what is the value of y? x+y+z=1x+y+z=1 2x+y−z=82x+y-z=8 x−y+z=−5
kirza4 [7]
If you have multiple equations with multiple variables, you can either do clever substitutions, or turn it into a matrix on which you can perform linear combinations or multiplications (Gauss elimination)

1  1   1  1
2  1  -1  8
1 -1   1  -5

(note how the above 3 rows represent the 3 equations, just got rid of the variables, plus sign and equals sign)

subtract row1 from row3, that eliminates x and z from row 3.

1  1   1  1
2  1  -1  8
0 -2   0  -6

divide row3 by -2, that will give y a factor of 1

1  1   1  1
2  1  -1  8
0 1   0  3

The last row now says y=3



3 0
3 years ago
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