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Galina-37 [17]
2 years ago
15

What are the real zeroes of x3 + 6 x2 – 9x - 54?

Mathematics
1 answer:
o-na [289]2 years ago
7 0

Answer:

Option B 3,-3,-6 is correct.

Step-by-step explanation:

We need to find real zeroes of x^3+6x^2-9x-54

Solving

x^3+6x^2-9x-54\\=(x^3+6x^2)+(-9x-54)

Taking x^2 common from first 2 terms and -9 from last two terms we get

=(x^3+6x^2)+(-9x-54)\\=x^2(x+6)-9(x+6)\\

Taking (x+6) common

(x+6)(x^2-9)\\

x^2-9 can be solved using formula a^2-b^2 = (a+b)(a-b)

=(x+6)((x)^2-(3)^2)\\=(x+6)(x+3)(x-3)

Putting it equal to zero,

(x+6)(x+3)(x-3) =0\\x+6 =0, x+3=0\,\, and\,\, x-3=0\\x=-6, x=-3\,\, and\,\,  x=3

So, Option B 3,-3,-6 is correct.

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What are the measures of ∠a, ∠b, ∠c and ∠d? Explain how to find each of the angles. measure
Alex787 [66]

Answer:

a=90° (given)

b=180°-90°-59° (angles on a straight line)

c=180°-59° (angles on a straight line)

d=59° (vertically opposite angles)

Step-by-step explanation:

I said the answer already

7 0
2 years ago
I NEED MEGA HELP WITH THIS QUESTION
katrin2010 [14]

Answer:

C. y =  -  \frac{1}{4} x - 2

Step-by-step explanation:

To find slope using coordinates, use the formula above.

(4, - 3) \: (0, - 2)→ \frac{ - 2 - ( - 3)}{0 - 4}→ \frac{ - 2 + 3}{ - 4} → -  \frac{1}{4}

Now, using the y = mx + b formula, plug in -  \frac{1}{4} as m (slope) and either coordinate as the x and y values. It looks like this:

- 3 =   - \frac{1}{4}(4)  + b

To solve for b, continue to use PEMDAS.

- 3 =   - \frac{1}{4}(4)  + b→ - 3 =  - 1 + b→ - 2 = b

Now use m and b to solve for your equation:

y =  -  \frac{1}{4} x - 2

The answer is C.

4 0
3 years ago
7x3 how much???????????????????????????????????????
elena55 [62]
7 x 3= 21 you can also use a calculator to help you
8 0
2 years ago
Read 2 more answers
mark invests 8000 in an account that pays 12% interest and 2000 in one that pays 8%. if he leaves the money in the accounts for
frez [133]

mark must leave it for 5.5 months or 5 and half moths to gain 5600 in interest​ .

<u>Step-by-step explanation:</u>

Here we have , mark invests 8000 in an account that pays 12% interest and 2000 in one that pays 8%. if he leaves the money in the accounts for the same length of time, We need to find how long must he leave it to gain 5600 in interest​ . Let's find out:

Let mark invests 8000 in an account that pays 12% interest and 2000 in one that pays 8% for time x months , So total interest gain is 5600 i.e.

⇒ \frac{8000(12)}{100}(x) +\frac{2000(8)}{100}(x) =5600

⇒ \frac{8000(12)+2000(8)}{100}(x) =5600

⇒ (80(12)+20(8))(x) =5600

⇒ (960+160)(x) =5600

⇒ (1020)(x) =5600

⇒ x =\frac{5600}{1020}

⇒ x =5.5

Therefore , mark must leave it for 5.5 months or 5 and half moths to gain 5600 in interest​ .

6 0
3 years ago
Ted has a credit card that uses the average daily balance method. For the first 9 days of one of his billing cycles, his balance
slega [8]
Your question doesn't say what are the options, but we can make some reasoning.

The average daily balance method is based, obviously, on the <span>average daily balance, which is the average balance for every day of the billing cycle. Therefore, in order to calculate the average daily balance, you need to sum the balance of every day and then divide it by the days of the billing cycle.
In your case:
ADB = (9</span>×2030 + 21×1450) / 30 = 1624 $

Now, in order to calculate the interest, you should first calculate the daily rate, since APR is usually defined yearly, and therefore:
rate = 0.23 ÷ 365 = 0.00063 

Finally, the expression to calculate the interest could be:
interest = ADB × rate × days in the billing cycle
or else:
<span>interest = ADB × APR ÷ 365 × days in the billing cycle

In your case:
interest = 1624 </span>× 0.23 ÷ 365 × 30
             = 30.70 $
4 0
3 years ago
Read 2 more answers
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