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ivanzaharov [21]
3 years ago
13

Order from least to greatest -2, 5, 1, 0, -3

Mathematics
2 answers:
Vedmedyk [2.9K]3 years ago
7 0

Answer:-3,-2,0,1,5

Step-by-step explanation:

VLD [36.1K]3 years ago
5 0
-3,-2,0,1,5 is the answer

i know this because i’m smart
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5q - p + p + 1, please help!
Mamont248 [21]
So basically you just add the like terms to simplify the equation. You have 5q-p+p+1 you can cancel out the both p’s because one is negative and one is positive. That leaves you with 5q + 1 they are not like terms so you cannot simplify them so your simplified equation is 5q +1
3 0
3 years ago
Write the equation for (-2,3) and (3,-1)
Bumek [7]

Answer:

y = -4/5x + 7/5

Step-by-step explanation:

Use slope intercept form to find the equation for the line:

y=mx+b

y= -4/5x + 7/5

8 0
3 years ago
Austin is going to the movie theater. It is 3 and3/5 miles from his house. Austin Takes his scooter, but it breaks down 2/3 of t
Nina [5.8K]
2 and 14/15
Because the first step of subtraction is common denominators
5 0
3 years ago
Read 2 more answers
What's the center of a circle whose equation is (x – 14)2 + (y + 21)2 = 64?
kvasek [131]

Answer:

The center of the circle is:

  • \left(a,\:b\right)=\left(14,\:-21\right)

Thus, option (2) is true.

Step-by-step explanation:

The circle equation is given by

\left(x-a\right)^2+\left(y-b\right)^2=r^2

here,

  • r =  raduis
  • center = (a, b)

Given the equation

\left(x-14\right)^2+\left(y+21\right)^2=64

\mathrm{Rewrite}\:\left(x-14\right)^2+\left(y+21\right)^2=64\:\mathrm{in\:the\:form\:of\:the\:standard\:circle\:equation}

\left(x-14\right)^2+\left(y-\left(-21\right)\right)^2=8^2

comparing with the circle equation

\left(x-a\right)^2+\left(y-b\right)^2=r^2

Therefore, the center of the circle is:

  • \left(a,\:b\right)=\left(14,\:-21\right)

Thus, option (2) is true.

7 0
3 years ago
Help a sis out please
DedPeter [7]
The answer to this question would be yes
4 0
3 years ago
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