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WARRIOR [948]
3 years ago
14

Simplify this expression : 2x(x-1)-3x^2-(5x-4)

Mathematics
1 answer:
Setler [38]3 years ago
6 0

Answer:

-x^2 - 7x + 4

Step-by-step explanation:

2x(x - 1) - 3x^2 - (5x - 4)

= 2x^2 - 2x - 3x^2 - 5x + 4

Adding like terms, we get:-

-x^2 - 7x + 4   (answer).


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1) x+30 = 40
soldier1979 [14.2K]

1)x+30=40

x=40-30

Answer :x=10

2)30-20+2x=10

10+2x=10

2x=0

Answer: x=0

3)3x-10+13=-2x+28

3x+3=-2x+28

3x+2x+3=28

3x+2x=28-3

5x=28-3

5x=25

x=5

4)13x-23-45=-7x+12

13x-68=-7x+12

13x+7x-68=12

13x+7x=12+68

20x=12+68

20x=80

x=4

5)2(x+4)=10x+24

2x+8=10x+24

2x-10x+8=24

2x-10x=24-8

-8x=24-8

-8x=16

x=-2

6)3(x-5)=1-(2x-4)

3x-15=1-(2x-4)

3x-15=1-2x+4

3x-15=5-2x

3x+2x-15=5

3x+2x=5+15

5x=5+15

5x=20

x=4

7)5x-10=15

5x=15+10

5x=25

x=5

8)x+4=x+6

4=6

no solution

PLEASE MARK ME AS BRAINLIEST

4 0
3 years ago
Challenge Yossi used to have a square garage with 246 ft of floor space. recently built an addition to it. The garage is still a
irina [24]

Considering the perimeter of a square, it is found that:

  • The length of one side of the garage​ originally was of 61.5 ft.
  • The length of one side of the garage​ now is of 92.25 ft.
  • The percent increase in the length of one​ side was of 50%.

<h3>What is the perimeter of a square?</h3>

The perimeter of a square of side length s is given by four times the length, that is:

P = 4s.

Before the change, the perimeter was of 246 ft, hence:

4s = 246

s = 246/4

s = 61.5.

The length of one side of the garage​ originally was of 61.5 ft.

After that, the perimeter increased by 50%, hence:

P = 246 x 1.5 = 369.

4s = 369

s = 369/4

s = 92.25.

The length of one side of the garage​ now is of 92.25 ft.

The percent increase is the increase divided by the initial value, hence:

(92.25 - 61.5)/61.5 = 50%.

The percent increase in the length of one​ side was of 50%.

More can be learned about the perimeter of a square at brainly.com/question/10489198
#SPJ1

4 0
1 year ago
The table lists how poverty level income cutoffs​ (in dollars) for a family of four have changed over time. Use the midpoint for
frez [133]

The poverty level cutoff in 1987 to the nearest dollar  was $10787.

<h3>How to find a midpoint?</h3>

The midpoint as the point that divides the line segment exactly in half having two equal segments. Therefore, the midpoint presents the same distance between the endpoints for the line segment. The midpoint formula is: \mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right).

For solving this exercise, first you need plot the points in a chart. See the image.

Your question asks to approximate the poverty level cutoff in 1987 to the nearest dollar using the midpoint formula. Note that the year 1987 is between 1980 and 1990, thus you should apply the midpoint formula from data for this year (1987).

\mathrm{Midpoint\:of\:}\left(1980,8429),\:\left(1990,13145):\quad \left(\frac{1990+1980}{2},\:\:\frac{13145+8429}{2}\right)\\\\ \\

\mathrm{Midpoint\:of\:}\left(1980,8429)\:=\left(\frac{1990+1987}{2},\:\frac{13145+3843}{2}\right)\\ \\ =\left(\frac{3977}{2},\:\frac{21574}{2}\right)

\mathrm{Midpoint\:of\:}\left(1980,8429)\:=\=(\frac{3977}{2},10787)

The answer for your question will be the value that you calculated for the y-coordinate. Then, the poverty level cutoff in 1987 to the nearest dollar  was $10787.

Read more about the midpoint segment here:

brainly.com/question/11408596

7 0
2 years ago
-8.3 divided by 0.25
gladu [14]

Answer:

-33.2

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
If s and t are integers greater than 1 and each is a factor of the integer n, which of the following must be a factor of n^{st}
andrey2020 [161]

Answer:

E) 1 and 2

Step-by-step explanation:

We are given that there are two integers (s and t) and they are factors of another integer (n). For example if s = 3 and t = 2, we can have n = 6.

Thus:

n^(st) = 6^(2*3) = 6^6 = (2^6)(3^6)

For the first condition: s^t = 3^2 is a factor of (2^6)(3^6)

For the second condition: (st)^2 = (3*2)^2 = 6^2 is a factor of 6^6

For the third condition: s+t = 3+2 = 5 is not a factor of 6^6 or (2^6)(3^6)

Therefore, only 1 and 2 are factors of n^(st)

6 0
3 years ago
Read 2 more answers
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