Ask question

Ask question

All categories

4 years ago

8

jet skis rent for $25 per hour plus a flat fee of $50. Noel has $200 to spend. what is the maximum value in the domain of this s

cenario

1 answer:

Nady [450]4 years ago

6 0

Answer:

$150

Step-by-step explanation:

25x4=100

100+50=150

so she has $50 to spend on other things

i dont know if this is what its asking or how

You might be interested in

AYUDAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA

Aleks04 [339]

Answer:

AyyDaaaaaaaaaaaaaaaaaaaaaaaaaa

6 0

3 years ago

a recipe for one pumpkin pie calls for 1 1/4 cups of sugar Elena only has 1/2 cup of sugar and she needs to make for pumpkin pie

seraphim [82]

Answer: she would need four and a half cups more of sugar.

Step-by-step explanation:

You have to add together all of them sugar she would have needed so (1 1/4 times 4) and then subtract what she already had and that gives you 4 and 1/2 cups she would need. Hope this helps

7 0

3 years ago

Find the circumference of a circle with a radius of 10 m. C = 2πr, where d=diameter and C = circumference. Use pi = 3.14.

Tju [1.3M]

Answer:

3.14×20

20=diameter

=62.8cm

4 0

3 years ago

Find the length of side ab give answer to 1dp<br><br>B is 62 degrees <br><br>And hypotenuse is 12cm

pshichka [43]

Iwteiwyeoe e to do that and i don’t even exist and i is so much more comfortable than that what do you

4 0

4 years ago

A sample of Iron-59 contains 50 mg. One hundred days later, the sample contains 10.75 mg. What is the half-life of iron-59, in d

exis [7]

Answer:

$t_{1/2}=45.09 d$

Step-by-step explanation:

We can use the decay equation:

$M=M_{0}e^{-\lambda t}$

M(0) is the initial mass
M is the mass after t (1000 days) time
λ is the decay constant

But:

$\lambda = ln(2)/t_{1/2}$

t(1/2) is the half-life.

So, we can rewrite the initial equation:

$M=M_{0}e^{-\frac{ln(2)}{t_{1/2}}t}$

Now, we just need to solve it for t(1/2):

$ln(\frac{M}{M_{0}})=-\frac{ln(2)}{t_{1/2}}t$

$t_{1/2}=-\frac{ln(2)}{ln(\frac{M}{M_{0}})}t$

$t_{1/2}=-\frac{ln(2)}{ln(\frac{10.75}{50})}100$

$t_{1/2}=45.09 d$

I hope it helps you!

5 0

3 years ago