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creativ13 [48]
4 years ago
13

The ratio of red marbles to blue marbles is 3:5. If there are 225 blue marbles total in the collection, how many of each color a

re there? Please show your work.
Mathematics
1 answer:
ziro4ka [17]4 years ago
8 0

Answer:

Red balls =  84     Blue balls =  140

Step-by-step explanation:

Ok so there are 225 marbles

And ratio here is Red : Blue = 3 : 5

So Red marbles = 3x whereas Blue marbles = 5x

Therefore,

3x + 5x = 225

8x = 225

x = 28.125 = 28

<u>Red balls = 28*3 = 84     Blue balls = 28*5 = 140</u>

(Pls check whether total no of balls is 224)

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toward the outside

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Simplify the expression (128x^5/8x)^1/2
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5 0
3 years ago
Simplify the following expression. (4x − 8)(4x + 8)
vitfil [10]

Answer:

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(4x − 8)(4x + 8)

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4 0
3 years ago
Consider the function f(x)=xln(x). Let Tn be the nth degree Taylor approximation of f(2) about x=1. Find: T1, T2, T3. find |R3|
Fynjy0 [20]

Answer:

R3 <= 0.083

Step-by-step explanation:

f(x)=xlnx,

The derivatives are as follows:

f'(x)=1+lnx,

f"(x)=1/x,

f"'(x)=-1/x²

f^(4)(x)=2/x³

Simialrly;

f(1) = 0,

f'(1) = 1,

f"(1) = 1,

f"'(1) = -1,

f^(4)(1) = 2

As such;

T1 = f(1) + f'(1)(x-1)

T1 = 0+1(x-1)

T1 = x - 1

T2 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2

T2 = 0+1(x-1)+1(x-1)^2

T2 = x-1+(x²-2x+1)/2

T2 = x²/2 - 1/2

T3 = f(1)+f'(1)(x-1)+f"(1)/2(x-1)^2+f"'(1)/6(x-1)^3

T3 = 0+1(x-1)+1/2(x-1)^2-1/6(x-1)^3

T3 = 1/6 (-x^3 + 6 x^2 - 3 x - 2)

Thus, T1(2) = 2 - 1

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T3(2) = 4/3

T3(2) = 1.333

Since;

f(2) = 2 × ln(2)

f(2) = 2×0.693147 =

f(2) = 1.386294

Since;

f(2) >T3; it is significant to posit that T3 is an underestimate of f(2).

Then; we have, R3 <= | f^(4)(c)/(4!)(x-1)^4 |,

Since;

f^(4)(x)=2/x^3, we have, |f^(4)(c)| <= 2

Finally;

R3 <= |2/(4!)(2-1)^4|

R3 <= | 2 / 24× 1 |

R3 <= 1/12

R3 <= 0.083

5 0
3 years ago
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