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12345 [234]
3 years ago
7

What is 617 rounded to the nearest ten?​

Mathematics
2 answers:
Ne4ueva [31]3 years ago
7 0

Answer:

620

Step-by-step explanation:

7 is near 10 so you round to the next number on the 10 table

Over [174]3 years ago
4 0

Answer:

617 roundend to the nearest ten is 620.

Step-by-step explanation:

617 is closer to 620 than it is to 610. So the nearest ten is 620.

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Find the distance between points P(2, 2) and Q(7, 4) to the nearest tenth.
kirill115 [55]

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We have the points P(2, 2) ans Q(7, 4). Substitute:

|PQ|=\sqrt{(7-2)^2+(4-2)^2}=\sqrt{5^2+2^2}=\sqrt{25+4}=\sqrt{29}\approx5.4

<h3>Answer: PQ = 5.4</h3>
8 0
3 years ago
1. What is the solution to the system below?<br> x+y=5<br> 1x- y=3
Alika [10]

Answer:

(4,1)

Step-by-step explanation:

x+y=5

x- y=3

Add the equations together to eliminate y

x+y=5

x- y=3

--------------------

2x = 8

Divide each side by 2

2x/2 = 8/2

x = 4

Now we can find y

x+y = 5

4+y = 5

Subtract 4 from each side

4+y-4 = 5-4

y =1

5 0
3 years ago
How do i find the volume of a cone with a radius of 9ft and a height of 24ft​
ycow [4]

Answer: V≈2035.75ft³

That is a small 3 after ft

HOPE THIS HELPS

8 0
2 years ago
NEED HELP Find values for a, b, c, and d so that the following matrix product equals the 2X2 identity matrix. Explain or show ho
ehidna [41]

We want to find the values of a, b, c, and d such that the given matrix product is equal to a 2x2 identity matrix. We will solve a system of equations to find:

  • b = 1
  • a = -1
  • c = -2
  • d = -1

<h3>Presenting the equation:</h3>

Basically, we want to solve:

\left[\begin{array}{cc}-1&2\\a&1\end{array}\right]*\left[\begin{array}{cc}b&c\\1&d\end{array}\right] = \left[\begin{array}{cc}1&0\\0&1\end{array}\right]

The matrix product will be:

\left[\begin{array}{cc}-b + 2&-c + 2d\\a*b + 1&a*c + d\end{array}\right]

Then we must have:

-b + 2 = 1

This means that:

b = 2 - 1 = 1

  • b = 1

We also need to have:

a*b + 1 = 0

we know the value of b, so we just have:

a*1 + b = 0

  • a = -1

Now the two remaining equations are:

-c + 2d = 0

a*c + d = 1

Replacing the value of a we get:

-c + 2d = 0

-c + d = 1

Isolating c in the first equation we get:

c = 2d

Replacing that in the other equation we get:

-(2d) + d = 1

-d = 1

  • d = -1

Then:

c  = 2d = 2*(-1) = -2

  • c = -2

So the values are:

  • b = 1
  • a = -1
  • c = -2
  • d = -1

If you want to learn more about systems of equations, you can read:

brainly.com/question/13729904

4 0
2 years ago
Pleaseeee help!!
kkurt [141]

Answer:

answer is A. cosine

Step-by-step explanation:

8 0
2 years ago
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