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liberstina [14]
2 years ago
10

Find the length indicated pleaseeeeeeee

Mathematics
1 answer:
cupoosta [38]2 years ago
6 0

number one will be {14-10= 4}

number two will be { x= -8}

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Which algebraic expression is equivalent to the expression below?<br> 6(3x-2)
SCORPION-xisa [38]

Answer:

18x - 12

Step-by-step explanation:

multiply each term in the parenthesis by the 6 outside ( distributive law)

6(3x - 2)

= (6 × 3x ) + (6 × - 2) = 18x +(- 12) = 18x - 12


8 0
4 years ago
Read 2 more answers
Identify all sets to which each number belongs.
gregori [183]

Answer:

14 is a positive integer, then it belongs to the set of natural numbers.

1 and 5/9 are rational numbers. The second is already a fraction and the first one, 1, is a natural number, but all the natural numbers can be written as the result of a fraction. For example: 1=6/6.

About the last number, I don't know if it's written correctly. That should be pi maybe, that is 3.14159.... In that case it's an irrational number.

Irrational numbers are all those real numbers that are not rational.

In general you have that:

ℕ ⊂ ℤ ⊂ ℚ ⊂ ℝ

ℕ. Natural numbers. It's the "smallest" one.

ℤ. Integers. Made with positive and negative natural numbers. Includes the natural numbers then.

ℚ. Rational numbers. Everything that can be written as a fraction. Includes both ℕ and ℤ.

ℝ. Real numbers. Any kind of number, fraction or not.

7 0
4 years ago
If there are 12 poles per 8 fishermen, then how many poles would be available for 34 fishermen?
aleksley [76]
About 22 fishing poles
5 0
3 years ago
Area of the shaded segment=
garik1379 [7]

The area of the entire sector is (\pi)(6^{2}) \left(\frac{60}{360} \right)=6\pi

The area of the triangle OAB is \frac{\sqrt{3}}{4}(6^{2})=9\sqrt{3}.

So, the area of the segment is \boxed{6\pi-9\sqrt{3}}

5 0
2 years ago
Simplify x^0yz^-3. Please explain
Alina [70]

Answer: \frac{y}{z^3}

Step-by-step explanation:

To simplify the expression given in the problem, you must apply the proccedure shown below:

1- According the Exponents Rules, you know the following:

a^0=1\\\\a^{-n}=\frac{1}{a^n}

2- Therefore, keeping the above on mind, you can simplify the expression given in the problem as you can see below:

x^0yz^{-3}=(1)yz^{-3}\\\\=yz^{-3}\\\\=y\frac{1}{z^3}\\\\=\frac{y}{z^3}

8 0
4 years ago
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