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den301095 [7]
3 years ago
11

Help. IM SO LOST ON THIS! ;(

Mathematics
1 answer:
castortr0y [4]3 years ago
3 0

Answer:

1. 4\frac{2}{3}

Step-by-step explanation:

For question 1, you need to know the ratio between the recipe and the amount in question.

So if in the recipe, it says it uses 3/4 cup of diced ham, and the question uses 1 cup of diced ham, you can divide 1 by 3/4 to get 4/3. This is how many times bigger the amount used in the question than the recipe.

Then it asks for how many cups of potatoes, to do this, you look at the recipe and how many potatoes it uses: 3.5 cups

To solve it then, you just do 3.5 x 4/3 to get 4\frac{2}{3} cups of potatoes

There's your answer.

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find the centre and radius of the following Cycles 9 x square + 9 y square +27 x + 12 y + 19 equals 0​
Citrus2011 [14]

Answer:

Radius: r =\frac{\sqrt {21}}{6}

Center = (-\frac{3}{2}, -\frac{2}{3})

Step-by-step explanation:

Given

9x^2 + 9y^2 + 27x + 12y + 19 = 0

Solving (a): The radius of the circle

First, we express the equation as:

(x - h)^2 + (y - k)^2 = r^2

Where

r = radius

(h,k) =center

So, we have:

9x^2 + 9y^2 + 27x + 12y + 19 = 0

Divide through by 9

x^2 + y^2 + 3x + \frac{12}{9}y + \frac{19}{9} = 0

Rewrite as:

x^2  + 3x + y^2+ \frac{12}{9}y =- \frac{19}{9}

Group the expression into 2

[x^2  + 3x] + [y^2+ \frac{12}{9}y] =- \frac{19}{9}

[x^2  + 3x] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}

Next, we complete the square on each group.

For [x^2  + 3x]

1: Divide the coefficient\ of\ x\ by\ 2

2: Take the square\ of\ the\ division

3: Add this square\ to\ both\ sides\ of\ the\ equation.

So, we have:

[x^2  + 3x] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}

[x^2  + 3x + (\frac{3}{2})^2] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}+ (\frac{3}{2})^2

Factorize

[x + \frac{3}{2}]^2+ [y^2+ \frac{4}{3}y] =- \frac{19}{9}+ (\frac{3}{2})^2

Apply the same to y

[x + \frac{3}{2}]^2+ [y^2+ \frac{4}{3}y +(\frac{4}{6})^2 ] =- \frac{19}{9}+ (\frac{3}{2})^2 +(\frac{4}{6})^2

[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =- \frac{19}{9}+ (\frac{3}{2})^2 +(\frac{4}{6})^2

[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =- \frac{19}{9}+ \frac{9}{4} +\frac{16}{36}

Add the fractions

[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{-19 * 4 + 9 * 9 + 16 * 1}{36}

[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{21}{36}

[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{7}{12}

[x + \frac{3}{2}]^2+ [y +\frac{2}{3}]^2 =\frac{7}{12}

Recall that:

(x - h)^2 + (y - k)^2 = r^2

By comparison:

r^2 =\frac{7}{12}

Take square roots of both sides

r =\sqrt{\frac{7}{12}}

Split

r =\frac{\sqrt 7}{\sqrt 12}

Rationalize

r =\frac{\sqrt 7*\sqrt 12}{\sqrt 12*\sqrt 12}

r =\frac{\sqrt {84}}{12}

r =\frac{\sqrt {4*21}}{12}

r =\frac{2\sqrt {21}}{12}

r =\frac{\sqrt {21}}{6}

Solving (b): The center

Recall that:

(x - h)^2 + (y - k)^2 = r^2

Where

r = radius

(h,k) =center

From:

[x + \frac{3}{2}]^2+ [y +\frac{2}{3}]^2 =\frac{7}{12}

-h = \frac{3}{2} and -k = \frac{2}{3}

Solve for h and k

h = -\frac{3}{2} and k = -\frac{2}{3}

Hence, the center is:

Center = (-\frac{3}{2}, -\frac{2}{3})

6 0
2 years ago
2.58, 2 5/8, 2.6, 2 2/3 least to greatest
8090 [49]

Answer:

2.58, 2.6, 2 5/8, 2 2/3

Step-by-step explanation:

2.58, 2.6, 2 5/8 can be converted into 2.625, and 2 2/3 can be converted into 2.66 with 6 being repeated over & over.

3 0
3 years ago
Which ratio is equivalent to 3/15
Rzqust [24]

Answer:

Step-by-step explanation:

The ratio of 6:30 would be equivalent to it.

4 0
3 years ago
⚠️⚠️please answer⚠️⚠️
Maurinko [17]

Answer:

The slope is -3/4 and the y-intercept is 1.

Step-by-step explanation:

B is the point where the line cross the y-axis, or vertical axis. Slope is the steepness of the line. Determined by rise over run. When the slope goes down 3 units, the slope goes to the right 4 units.

6 0
2 years ago
Read 2 more answers
The ratio of money in Obi's wallet to Rudy's wallet one day was 5:2.
mamaluj [8]

Answer:

The amount that Obi initially had was £20

Step-by-step explanation:

Let

x ----> amount that Obi initially has

y ----> amount that Rudy has

we know that

\frac{x}{y} =\frac{5}{2}

x=2.5y ----> equation A

x-20=y-8

y=x-20+8

y=x-12 ----> equation B

Solve the system by substitution

substitute equation A in equation B

y=(2.5y)-12

solve for y

2.5y-y=12\\1.5y=12\\y=8

Find the value of x

x=2.5(8)=20

therefore

The amount that Obi initially had was £20

4 0
3 years ago
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