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ELEN [110]
3 years ago
11

Someone help me answer this please

Mathematics
1 answer:
ELEN [110]3 years ago
5 0

Answer:

Step-by-step explanation:

A is the mid point

AY = AX

5x - 6 = 3x   {Add 6 to both side}

5x = 3x + 6     {Subtract 3x from both side}

5x - 3x = 3x + 6 - 3x

2x = 6    {Divide both the side by 2}

2x/x = 6/2

x = 3

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There are 4 aces and 4 kings in a standard deck of playing cards. you pick one random card at random. What is the probability of
hichkok12 [17]

Answer:2/3

Step-by-step explanation:There are 52 cards in a standard deck: 13 ordinal cards (Ace - 10, Jack, Queen, King) and 4 of them - one to each suit (hearts, diamonds, clubs, spades) and so we have

4

×

13

=

52

.

There are 8 cards that fit the question (4 each of aces and kings).

And so in a random draw, the odds of drawing one of those 8 cards out of the total number of 52 is:8/52

which we can simplify:

8/52=2/13

8 0
2 years ago
A line with a slope of -7 passes through the points (u,0) and (8,-7) what is the value of u?
laila [671]

Answer:

u = 7

Step-by-step explanation:

Using the slope intercept formula:

\frac{y2 - y1}{x2 - x1}  = slope

Substitute our values from the points and the known slope:

\frac{-7 - 0}{8 - u} = -7

Now we multiply both sides by (8 - u) to isolate the x:

(8-u) x \frac{-7}{8 - u} = -7 (8 - u)

Next we add 56 to both sides:

-7 = -56 + 7u

Finish off by dividing both sides by 7:

7u = 49

u = 7

6 0
3 years ago
Of the 8 students in the chess club, three will represent the club at an upcoming competition. How many different 3-person teams
xz_007 [3.2K]
I think that this is a combination problem. From the given, the 8 students are taken 3 at a time. This can be solved through using the formula of combination which is C(n,r) = n!/(n-r)!r!. In this case, n is 8 while r is 3. Hence, upon substitution of the values, we have

C(8,3) = 8!/(8-3)!3!
C(8,3) = 56

There are 56 3-person teams that can be formed from the 8 students. 
6 0
3 years ago
Read 2 more answers
Secants P N and L N intersect at point N outside of the circle. Secant P N intersects the circle at point Q and secant L N inter
JulijaS [17]

Answer:

A circle is shown. Secants P N and L N intersect at point N outside of the circle. Secant P N intersects the circle at point Q and secant L N intersects the circle at point M. The length of P N is 32, the length of Q N is x, the length of L M is 22, and the length of M N is 14.

In the diagram, the length of the external portion of the secant segment PN is <u>X</u>

The length of the entire secant segment LN is <u>36</u>.

The value of x is <u>15.74</u>

Step-by-step explanation:

Snap

Jona_Fl16

7 0
3 years ago
Read 2 more answers
What statement is true?
givi [52]

Answer:

\frac{18}{32}>\frac{16}{32}

Step-by-step explanation:

We need to find which statements are true.

Solution to find the same we will solve each statement and will conclude the same.

1.  \frac{14}{21}>\frac{17}{24}

Now On solving we get;

\frac{14}{21} = 0.66

\frac{17}{24}=0.70

So we can see that 0.70 > 0.66

Hence The given statement is False.

2. \frac{18}{32}>\frac{16}{32}

Now On solving we get;

\frac{18}{32}=0.5625

\frac{16}{32}= 0.5

So we can see that 0.5625 > 0.5

Hence The given statement is True.

3.  \frac{20}{15}

Now On solving we get;

\frac{20}{15} = 1.33

\frac{28}{23}=1.2

So we can see that 1.33 > 1.2

Hence The given statement is False.

4.  \frac{29}{35}

Now On solving we get;

\frac{29}{35}= 0.82

\frac{20}{30}= 0.66

So we can see that 0.82 > 0.66

Hence The given statement is False.

7 0
3 years ago
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