Question

Given right triangle GYK, what is the value of tan(G)?

Answer 1

Answer:

The value of tan(G) in the  right triangle GYK Is $\sqrt{3}$

Step-by-step explanation:

Given

Measure of angle at $G=60^{\circ}$

Measure of angle at $Y=30^{\circ}$

Measure of angle at $K=90^{\circ}$

To find:

$\tan (G)=?$

Solution:

In trigonometry we know that

$\tan G=\frac{\sin G}{\cos G}$

$G=60^{\circ}$

So,

$\sin (60)=\frac{\sqrt{3}}{2}$

$\cos (60)=\frac{1}{2}$

Substituting in the formula we have,

$\tan G=\frac{\frac{\sqrt{3}}{2}}{\frac{1}{2}}$

$\tan G=\frac{\sqrt{3}}{2} \times \frac{2}{1}$

$\tan G=\frac{\frac{\sqrt{3}}{2}}{\frac{1}{2}}$

$\tan G=\sqrt{3}$

Result:

Thus the value of $\tan G=\sqrt{3}$

Answer 2

Answer:

The answer is $\sqrt{3$

Step-by-step explanation:

Tan(G) = opposite side

              adjacent side

Tan(G) = $\frac{\sqrt{3} }{1}$

Tan(G) = $\sqrt{3}$