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4 years ago

Use the formula A = h(b1 + b2). What is the area of the trapezoid? square units

Mathematics

2 answers:

deff fn [24]4 years ago

4 0

Only use h=trapezoid's height.

b=base

jarptica [38.1K]4 years ago

3 0

Answer:

75 square units

Step-by-step explanation:

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The area of a triangle is 14 square units it has a side length of a and b what is the value of b if a is 1/5

Ilia_Sergeevich [38]

Answer:

140 ft

Step-by-step explanation:

Given data

Area= 14 square feet

Height a = 1/5 ft

Base b=????

We know that the area of a triangle is given as

Area= (1/2)B*H

substitute

14= 1/2* B* 1/5

14= B/10

cross multiply

B= 140

Hence the base is 140 ft

7 0

3 years ago

The result of subtracting 2 from its opposite is

belka [17]

It’s four because you subtract 2 minus negative 2

4 0

4 years ago

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A bulletin board measuring 28 dm long was divided among three subject areas in the ratio 2:2:3. How much space was alothed for e

Sphinxa [80]

Answer: Space was alloted for each subject is 8 dm, 8 dm, 12 dm.

Explanation:

Since we have given the length of bulletin board =28 dm

Let the share of three subject areas be 2x,2x,3x

According to question,

$2x+2x+3x=28\\7x=28\\x=\frac{28}{7}\\x=4dm$

so x=4 dm

Now,

Space was alloted for each subject is given as below:

First subject = $2x=2\times 4=8 dm$

Second subject = $2x=2\times 4=8 dm$

Third subject = $3x=3\times 4=12 dm$

4 0

3 years ago

Circle X is shown. Points W, Y, and Z are on the circle. Lines are drawn through each point on the circle.

Dimas [21]

Answer:

Its point X

Step-by-step explanation:

Just did it on edge 2020

6 0

4 years ago

Read 2 more answers

1) State the amplitude, period, phase shift, vertical shift and graph

bogdanovich [222]

Answer:

See answers and explanations below (along with a visual graph)

Step-by-step explanation:

For the function $y=acos(b(x+c))+d$ :

Amplitude: $|a|$

Period: $\frac{2\pi}{|b|}$

Phase shift: $\frac{-c}{b}$

Vertical shift: $d$

Therefore, for $y=2cos(\frac{2}{3}(\theta+\pi))-1$ :

Amplitude: $|a|=|2|=2$ , which is 2 units above and below the midline (see d)

Period: $\frac{2\pi}{|b|}=\frac{2\pi}{|\frac{2}{3}|}=\frac{2\pi}{\frac{2}{3}}=3\pi$ , so the cycle will repeat every 3π units

Phase shift: $\frac{-c}{b}=\frac{-\frac{2\pi}{3} }{\frac{2}{3} }=-\pi$ , or π units to the left

Vertical shift: $d=-1$ , or 1 unit down

3 0

3 years ago