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3 years ago

I need help with this. Please help!

Mathematics

1 answer:

olga55 [171]3 years ago

7 0

Answer:

61%

Step-by-step explanation:

122 squares out of 200 hundred (122/200) is simplified as 61/100, so 61%

It helps to count each side of the large squares. 10 squares by 10 squares on each side = 100 squares total, and there are two squares, so double the 100.

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(WILL GIVE BRAINLIEST) In right ∆ABC with m∠B=30°, AC = 4. Find HB

goblinko [34]

Answer:

HB would be 90 degrees

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Find the values of x and y for which the lines are parallel.

bearhunter [10]

The answer: " x = 68, y = 72 " .
____________________________
Explanation:
________________________________________
46 + (x - 3) + (y - 3) = 180 .

46 + 1(x - 3) + 1(y-3) = 180 .

46 + 1x - 3 + 1y - 3 = 180 .

46 - 3 - 3 + 1x + 1y = 180 .

40 + x + y = 180 ;

Subtract "40" from EACH SIDE of the equation:
______________________________________
40 + x + y - 40 = 180 - 40 ;

to get:

x + y = 140 ;
_____________________________________
Now:
_____________________________________
65 = (x - 3) ;

↔ x - 3 = 65 ;

Add "3" to EACH SIDE of the equation;

    x - 3 + 3 = 65 + 3 ;

to get:

           x = 68 .
______________________________
Now:

Since: "x + y = 140" ;

Let us plug in our known value, "68" ; for "x" ;

to solve for "y" ;
__________________________________
   x + y = 140 ;

  68 + y = 140 ;

↔ y + 68 = 140 ;

Subtract "68" from EACH SIDE of the equation; to isolate "y" on one side of the equation; and to solve for "y" ;
______________________________________________
   y + 68 - 68 = 140 = 68 ;

                  y = 72 .
______________________________________________
So, solve for "x" and "y".

x = 68, y = 72 .
_______________________________________________

5 0

3 years ago

Ok so do I subtract 5 from x and 5 Orr am I solving wrong i don’t know this is confusing.

Aleksandr [31]

Answer:

no you dont

Step-by-step explanation:

4 0

3 years ago

Some transportation experts claim that it is the variability of speeds, rather than the level of speeds, that is a critical fact

scZoUnD [109]

Answer:

Explained below.

Step-by-step explanation:

The claim made by an expert is that driving conditions are dangerous if the variance of speeds exceeds 75 (mph)².

(1)

The hypothesis for both the test can be defined as:

H₀: The variance of speeds does not exceeds 75 (mph)², i.e. σ² ≤ 75.

Hₐ: The variance of speeds exceeds 75 (mph)², i.e. σ² > 75.

(2)

A Chi-square test will be used to perform the test.

The significance level of the test is, α = 0.05.

The degrees of freedom of the test is,

df = n - 1 = 55 - 1 = 54

Compute the critical value as follows:

$\chi^{2}_{\alpha, (n-1)}=\chi^{2}_{0.05, 54}=72.153$

Decision rule:

If the test statistic value is more than the critical value then the null hypothesis will be rejected and vice-versa.

(3)

Compute the test statistic as follows:

$\chi^{2}=\frac{(n-1)\times s^{2}}{\sigma^{2}}$

$=\frac{(55-1)\times 94.7}{75}\\\\=68.184$

The test statistic value is, 68.184.

Decision:

$cal.\chi^{2}=68.184$

The null hypothesis will not be rejected at 5% level of significance.

Conclusion:

The variance of speeds does not exceeds 75 (mph)². Thus, concluding that driving conditions are not dangerous on this highway.

7 0

3 years ago

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HACTEHA [7]

Answer:

Is that a magic spell??

Step-by-step explanation:

???

6 0

3 years ago