Answer:
They sold 60 muffins and 60 cookies yesterday
It is a LCM problem
Step-by-step explanation:
6 muffins together
20 cookies together
To sell the same amount of muffins and cookies,
Find the lowest common multiple of 6 muffins and 20 cookies
6 muffins = 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78
20 cookies = 40, 60, 80
The lowest common multiple of 6 muffins and 20 cookies is 60
Therefore,
They sold 60 muffins and 60 cookies yesterday
It is a LCM problem
Answer:a) L.C.M OF 2,3,5 is 30
THEREFORE=60/30+15/30÷10/30-6/30
=60/30+15/30×30/10-6/30(DMAS)
=60/30+3/2-6/30
=60+45/30 -6/30(ADDITION FIRST THEN SUBTRACTION.
=105/30-6/30
=105-6/30
=99/30
=33/10
b)(3+1/2)÷(2-1/2)=L.C.M IS 2,=(6+1/2)÷(4-1/2)=7/2÷3/2=7/3
Answer:
3n-7
Step-by-step explanation:
Answer:
12
Step-by-step explanation:
So, she practices 12 hrs per week, and already has practiced 3 hrs this week.
This means she has 9 hrs left to practice.
3/4 of an hour is one session, so to find out the number of sessions she needs, you have to do (9 hours)/(one session)
which is basically 9 / ( 3/4)
She needs 12 more sessions.
Step 1: move all terms to one side
7 + 2x^2 - 10x = 0
Step 2: Use the quadratic formula
X = 10 + 2(square root of 11). 10-2 _/—-11
————————————. ——————
4. , 4
Step 3: Simplify solutions
X= 5 + (square root of 11) 5 - (square root 11)
——————————- , ————————
2. 2
