In ΔJKL, the measure of ∠L=90°, the measure of ∠J=25°, and KL = 26 feet. Find the length of LJ to the nearest tenth of a foot.
1 answer:
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<h3>Answer:</h3>
A. +-5x+14x+-35
+9x-35
B.
C.
D.
Step-by-step explanation:
A. (3x*2x)+(3x*-5)+(7*2x)+(7*-5)
Multiply and simplify.
+9x-35
B. ()+(
-3x)+(2x
)+(2x
)
Multiply and simplify.
C.
Multiply and simplify.
D.
Multiply and simplify.
I hope this helps!
But you should really do this yourself.