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3 years ago

Which ordered pairs make the inequality true?

Mathematics

1 answer:

matrenka [14]3 years ago

6 0

Answer:

The ordered pairs (-2,3) and (5,1) make the inequality true.

Step-by-step explanation:

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Hatshy [7]

If f(x) = 0, means " For which value of x, f(x) or y = 0".
Then f(x) = 0 for all points of the graph that intersects the x-axis, that is:

for x = -2, for x = 1 and for x = 3 (Answer -2, 1 or 3 only)

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4 years ago

A) Na osi liczbowej odległość między liczbami -3,2 i 2,6 jest równa ...

Damm [24]

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3 years ago

Solve the quadratic expression by completing the square. 2p^2=6p-20

Leviafan [203]

Answer:

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Step-by-step explanation:

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3 years ago

Bradley has 64 1-inch cubic blocks.He uses all the blocks to build a rectangular prism that is 2 inches high and 2 inches wide.H

Lynna [10]

Answer:

The length of the rectangular prism is $16\ in$

Step-by-step explanation:

step 1

Find the volume of the 64 1-inch cubic blocks

The volume of one cubic block is

$V=(1)^{3}=1\ in^{3}$

the volume of 64 cubic blocks is

$V=64(1)=64\ in^{3}$

step 2

Find the length of the rectangular prism

The volume of the rectangular prism is equal to

$V=LWH$

we have

$V=64\ in^{3}$

$W=2\ in$

$H=2\ in$

substitute and solve for L

$64=L(2)(2)$

$64=4L$

$L=64/4=16\ in$

5 0

3 years ago

Find the distance between the points (a1, b1) and (a2, b2).

Molodets [167]

Step-by-step explanation:

Let there be point X whose coordinates are (a2,b2) and point Y whose coordinates are (a1,b1)

Using distance formula ,

$\sqrt{ ({a}^{2} - {a}^{1}) + ( {b}^{2} - {b}^{1} ) }$

$where \: {a}^{2 } > {a}^{1} \: and \: \: {b}^{2} > {b}^{1}$

$If \: {a}^{1} > {a}^{2} \: and \: {b}^{1}>{b}^{2}$

Distance formula will be

$\sqrt{({a}^{1} - {a}^{2}) + ({b}^{1} - {b}^{2})}$

8 0

3 years ago