Igor's taxable income is the difference between the amount
he earns annually and the amount he earns as exemptions.
Response:
- The amount he pays in annual state income tax is;<u> $1,497</u>
<h3>Which methods are used to calculate income tax?</h3>
Given;
Annual earnings = $57,900
State tax rate = 3%
Amount earned in exemption = $8,000
Required:
The amount Igor pays in annual state income tax.
Solution;
Taxable Income = Annual Income - Exemptions
Therefore;
Igor's taxable income = $57,900 - $8,000 = $49,900
Taxable Income × Tax rate = Amount paid as tax
- The amount he pays is therefore; $49,900 × 3% = <u>$1,497</u>
Learn more about income tax here:
brainly.com/question/25278778
Answer:
X=3/2 or 1.732
Step-by-step explanation:
X^2-4+1=0
Combine like terms
-4 + 1 = -3
X^2-3=0
add 3 to both sides
X^2= 3
X= 3/2
Answer:
x
=
2
±
√
7
Explanation:
there are no whole numbers which multiply to - 3
and sum to - 4
we can solve using the method of
completing the square
the coefficient of the
x
2
term is 1
∙
add subtract
(
1
2
coefficient of the x-term
)
2 to
x2
−
4
x
⇒
x
2
+2(−
2
)
x
+
4
−
4
−
3
=
0
⇒
(
x
−
2
)2
−
7
=0
⇒
(
x
−
2
)
2
=
7
take the square root of both sides
⇒
x
−
2
=
±
√
7
←
note plus or minus
⇒
x
=
2
±
√
7←
exact solutions
Top, right because the numbers are increasing by the same amount (2 in this case).
Answer:
B is True
A, C. D are false
Step-by-step explanation:
Given :
Sample size, n = 120
Mean diameter, m = 10
Standard deviation, s = 0.24
Confidence level, Zcritical ; Z0.05/2 = Z0.025 = 1.96
The confidence interval represents how the true mean value compares to a set of values around the mean computed from a set of sample drawn from the population.
The population here is N = 10000
To obtain
Confidence interval (C. I) :
Mean ± margin of error
Margin of Error = Zcritical * s/sqrt(n)
Margin of Error = 1.96 * 0.24/sqrt(120)
Confidence interval for the 10,000 ball bearing :
10 ± 1.96 * (0.24) / sqrt(120)
Hence. The confidence interval defined as :
10 ± 1.96 * (0.24) / sqrt(120) is the 95% confidence interval for the mean diameter of the 10,000 bearings in the box.
