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2 years ago

Why do you need to find the common denominator to simplify

Mathematics

1 answer:

Vera_Pavlovna [14]2 years ago

8 0

Because then you can just add the tops like they are

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How do i find the answer?

Radda [10]

by just addding it and diving

6 0

3 years ago

For a business meeting, Jenna is making copies of her presentation. The more people

Fantom [35]

Answer:

Independent: The people who attend.

Dependent: The copies she has to make.

Step-by-step explanation:

She will make a certain amount of copies depending of how many people attend.

3 0

2 years ago

What is 4 4/5 + 1 1/3?

Dafna1 [17]

Answer:

$\frac{92}{15}$

Step-by-step explanation:

change to improper

$\frac{24}{5} + \frac{4}{3}$

this gives us

$\frac{92}{15}$

final answer

plz mark as brainliest

7 0

2 years ago

Read 2 more answers

The figures below are made out of circles, semicircles, quarter circles, and a square. Find the area and the perimeter of each f

WITCHER [35]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)\\A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)\\C=6\pi\ cm$

Applying the Pythagorean Theorem

The hypotenuse of right triangle is equal to

$AC=\sqrt{12^2+12^2}\\AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

4 0

3 years ago

A farmer has a collapsable grain bag which can expand both vertically and horizontally as he needs it to. He wants to find a fun

bija089 [108]

Answer:

$3x^{3}+15x^{2}+x+5$

Step-by-step explanation:

We are told that the area of the bag can be represented by the function $f(x)=3x^{2} +1$ and as the bag is raised up its height can be represented by the function $g(x)=x +5$ .

Since we know that we can find volume of cuboid by multiplying base area to its height. We are given area and height of bag as functions. Now we will find volume of the bag by multiplying these functions.

$\text{Volume of collapsible bag}=f(x)*g(x)$

$\text{Volume of collapsible bag}=(3x^{2}+1)*(x +5)$

After using distributive property we will get,

$\text{Volume of collapsible bag}=3x^{2}(x+5)+1(x+5)$

$\text{Volume of collapsible bag}=3x^{3}+15x^{2}+x+5$

Therefore, the collapsible bag can hold $3x^{3}+15x^{2}+x+5$ grain.

6 0

3 years ago