Answer:
x = 14
EHF = 15 degree GHF = 75 degree
Step-by-step explanation:
(x+1) + (5x+5) = 90
(x+5x)+ (1+5) = 90
6x + 6 = 90
6x = 90-6
6x = 84
x = 84/6
x = 14
EHF + GHF = 90 degree
EHF = x+1
= 14 + 1 = 15
= 15 degree
GHF = 5x+5
= 14 x 5 (+5) = 70 + 5
= 75 degree
EHF = 15 degree GHF = 75 degree
Answer:
Domain: (-∞, ∞) or All Real Numbers
Range: (0, ∞)
Asymptote: y = 0
As x ⇒ -∞, f(x) ⇒ 0
As x ⇒ ∞, f(x) ⇒ ∞
Step-by-step explanation:
The domain is talking about the x values, so where is x defined on this graph? That would be from -∞ to ∞, since the graph goes infinitely in both directions.
The range is from 0 to ∞. This where all values of y are defined.
An asymptote is where the graph cannot cross a certain point/invisible line. A y = 0, this is the case because it is infinitely approaching zero, without actually crossing. At first, I thought that x = 2 would also be an asymptote, but it is not, since it is at more of an angle, and if you graphed it further, you could see that it passes through 2.
The last two questions are somewhat easy. It is basically combining the domain and range. However, I like to label the graph the picture attached to help even more.
As x ⇒ -∞, f(x) ⇒ 0
As x ⇒ ∞, f(x) ⇒ ∞
Answer:
The price of the cake is $24 and the price of the Pie is $15
Step-by-step explanation:
Given
<em>Represent price of Cake with C and Price of Pie with P</em>

Cakes sold = 8
Pies sold = 14

Required
Determine C and P
To represent the cakes and pies sold, we have the following expression

Substitute 9 + P for C

Open the bracket

Collect Like Terms


Divide both sides by 22


Recall that



<em>Hence, the price of the cake is $24 and the price of the Pie is $15</em>
Answer:

Step-by-step explanation:
We can find the horizontal component of force he applied by using the formula for work:

Solving for force, we have:

However he applied the original force at an angle of
to the horizontal. This force of 16 newtons is only the horizontal component of that force. To find the magnitude of the original force, we can use basic trigonometry:
