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kupik [55]
3 years ago
8

Which expression is equivalent to 7a^2b + 10a^2b^2 + 14a^2b^3?

Mathematics
2 answers:
GuDViN [60]3 years ago
7 0

Answer:

Option: B is the correct answer.

           B) a^2b(7+10b+14b^2)

Step-by-step explanation:

We are given an algebraic expression in terms of the variable 'x' and 'y' as:

7a^2b+10a^2b^2+14a^2b^3

Now we are asked to find the expression that is equivalent to the above expression.

We could clearly observe that each of the term in the expression has a common term as: a^2b

Hence, we take out common this common term and write the remaining expression in  bracket as:

                    a^2b(7+10b+14b^2)

vladimir1956 [14]3 years ago
3 0
7a^2b + 10a^2b^2 + 14a^2b^3 =
a^2b (7 + 10b + 14b^2) <==
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Can please someone help me out and explain it step by step. Thank you
Anit [1.1K]

Answer:x=7, \ y=-2

Step-by-step explanation:

Given

Equations are 3x-y=23 and 2x+3y=8

take 3x-y=23

y=3x-23

Put the value of y in another equation

\Rightarrow 2x+3(3x-23)=8\\\Rightarrow 2x+9x-69=8\\\Rightarrow 11x=77\\\Rightarrow x=7

Put the value of x in y

y=3(7)-23=21-23=-2

Hence, x=7, \ y=-2

7 0
3 years ago
What is the quotient?
Zepler [3.9K]

Answer:

= \dfrac{1}{5^{9}}

Step-by-step explanation:

When dividing values with exponents, we simply need to subtract the numerators exponent to the denominators exponent.

So we have:

\dfrac{5^{-6}}{5^{3} }

= 5^{-6 - 3}

= 5^{-9}

Now since we have a negative exponent, we can get the reciprocal of the value to make it positive.

= \dfrac{1}{5^{9}}

7 0
3 years ago
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I will send you a pic of the question... &lt;3​
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Answer:

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Step-by-step explanation:

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6 0
3 years ago
How you will find out the value of 'n ' ?
saw5 [17]

Answer:

I don't know

Step-by-step explanation:

How you will find out the value of 'n ' ?

[ n! × 2^( n-4 ) / { 4! × ( n-4 )! } ] = [ n! × 2^( n-5 ) / { 5! × ( n-5 )! } ]

8 0
3 years ago
The sum of the arithmetic progression 4, ..., 76 is 1920. Find the number of terms and the common difference.​
valkas [14]

<u>Number of terms = 48</u>

<u>common difference = 1.5</u>

This question involves the concept of Arithmetic Progression.

  • The formula for sum of an arithmetic progression series with first and last term given is;

S_{n} = \frac{n}{2}(a + l)

where;

a = first term

l = last term

n = number of terms

  • From the given sequence, we see that;

first term; a = 4

last term; l = 76

Sum of A.P; S_{n} = 1920

  • Plugging in relevant values into the sum of an AP formula, we have;

1920 = \frac{n}{2}(4 + 76)

simplifying this gives;

1920 = 40n

n = 1920/40

n = 48

  • Formula for nth term of an AP is;

t_{n} = a_{1} + (n - 1)d

where;

a_{1} is first term

d is common difference

n is number of term

t_{n} is the nth term in question

the 48th term is 76

Thus;

76 = 4 + (48 - 1)d

76 - 4 = 47d

72 = 47d

d = 72/47

d ≈ 1.5

Thus;

Number of terms = 48

common difference = 1.5

Read more at; brainly.com/question/16935540

4 0
3 years ago
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