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Savatey [412]
3 years ago
9

Round to the nearest hundredth

Mathematics
1 answer:
Charra [1.4K]3 years ago
7 0
Hey there,
1st hat = x
2nd hat = 2x
3x = $75.12
x= $75.12 / 3
  = $25.04
2x = $25.04 x 2
     =$50.08
     = $50.10 (round off)

Hope this helps ^_^

~Top
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If alvin sold 60% of his baseball cards, gave away 30% of those that were left, and still had 40 baseball cards in his possessio
kipiarov [429]

Answer:

The number of baseball card to begin with is 143

Step-by-step explanation:

Let The number of baseball cards = x

The number of sold baseball card = 60% of x

                                                         = 0.6 x

The number of left baseball card = x - 0.6 x = 0.4 x

The number of card gave away = 30 % of left cards

                                                     = 0.3 × 0.4 x = 0.12 x

The number of card left in his possession = 40

So, 0.6 x + 0.12 x + 40 = x

Or,  40 = x - 0.6 x - 0.12 x

Or,  40 = 0.28 x

∴   x = \frac{40}{0.28}  =  142.85 ≈ 143

Hence The number of baseball card to begin with is 143  Answer

3 0
3 years ago
A car dealership decreased the price of a certain car by 4%. The original price was
serg [7]
%change=100(final-initial)/initial, 

%change=100(New price-Original price)/Original price

(Original price*%change)/100=New price-Original price

New Price=(Original price*%change+100*Original price)/100

New Price=Original price(100+%change)/100

Since %change is -4%...

New Price=0.96(Original price)

...

Since original price is $45400

New Price=0.96(45400)

New Price=$43584


6 0
3 years ago
Read 2 more answers
If f(x)=3x and g(x)=1/x, what is the domain of (g o f)(x)?
Neko [114]

Here it is given that f(x)=3x and g(x)=1/x

We have to find the domain of (g o f)(x)

Now it is given that f(x) = 3x

and it is also given that g(x) = 1/x

so (g o f)(x) = g( f(x) ) = g( 3x )

which comes out to be 1 / 3x

The domain of the expression is all the real numbers except where the expression is undefined so the domain of the given expression is all real numbers except 0.

5 0
3 years ago
Solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations.
Anuta_ua [19.1K]

Answer:

c

Step-by-step explanation:

First, we can transform this into a matrix. The x coefficients will be the first ones for each row, the y coefficients the second column, etc.

\left[\begin{array}{cccc}1&-2&3&-2\\6&2&2&-48\\1&4&3&-38\end{array}\right]

Next, we can define a reduced row echelon form matrix as follows:

With the leading entry being the first non zero number in the first row, the leading entry in each row must be 1. Next, there must only be 0s above and below the leading entry. After that, the leading entry of a row must be to the left of the leading entry of the next row. Finally, rows with all zeros should be at the bottom of the matrix.

Because there are 3 rows and we want to solve for 3 variables, making the desired matrix of form

\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right] for the first three rows and columns. This would make the equation translate to

x= something

y= something

z = something, making it easy to solve for x, y, and z.

Going back to our matrix,

\left[\begin{array}{cccc}1&-2&3&-2\\6&2&2&-48\\1&4&3&-38\end{array}\right] ,

we can start by removing the nonzero values from the first column for rows 2 and 3 to reach the first column of the desired matrix. We can do this by multiplying the first row by -6 and adding it to the second row, as well as multiplying the first row by -1 and adding it to the third row. This results in

\left[\begin{array}{cccc}1&-2&3&-2\\0&14&-16&-36\\0&6&0&-36\end{array}\right]

as our matrix. * Next, we can reach the second column of our desired matrix by first multiplying the second row by (2/14) and adding it to the first row as well as multiplying the second row by (-6/14) and adding it to the third row. This eliminates the nonzero values from all rows in the second column except for the second row. This results in

\left[\begin{array}{cccc}1&0&10/14&-100/14\\0&14&-16&-36\\0&0&96/14&-288/14\end{array}\right]

After that, to reach the desired second column, we can divide the second row by 14, resulting in

\left[\begin{array}{cccc}1&0&10/14&-100/14\\0&1&-16/14&-36/14\\0&0&96/14&-288/14\end{array}\right]

Finally, to remove the zeros from all rows in the third column outside of the third row, we can multiply the third row by (16/96) and adding it to the second row as well as multiplying the third row by (-10/96) and adding it to the first row. This results in

\left[\begin{array}{cccc}1&0&0&-5\\0&1&0&-6\\0&0&96/14&-288/14\end{array}\right]

We can then divide the third row by -96/14 to reach the desired third column, making the reduced row echelon form of the matrix

\left[\begin{array}{cccc}1&0&0&-5\\0&1&0&-6\\0&0&1&-3\end{array}\right]

Therefore,

x=-5

y=-6

z=-3

* we could also switch the second and third rows here to make the process a little simpler

3 0
3 years ago
Yesterday, The tempature at noon was 11.4. By midnight, the temperature had decreased by 15.7 degrees. The temperature then decr
tamaranim1 [39]

the temp at 2 am is -6.7 degrees

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