Question

The base of a solid oblique pyramid is an equilateral triangle with a base edge length of 18 inches. A solid oblique pyramid has an equilateral triangle base with an edge length of 18 inches. What is the height of the triangular base of the pyramid? 9 √ 2 in. 9 √ 3 in. 18 √ 2 in. 18 √ 3 in.

Answer 1

Answer:

b.$9\sqrt{3}in$

Step-by-step explanation:

We are given that

Length of equilateral triangle=a=18 in

Base of oblique pyramid is an equilateral triangle.

We have to find the height of the triangular base of the pyramid

Height of the triangular base of the pyramid,h=$acos\theta$

We know that each angle of equilateral triangle =60 degree

$\theta=\frac{60}{2}=30^{\circ}$

Substitute the values

Height of triangular base of the pyramid,h=$18cos30=18\times \frac{\sqrt 3}{2}$in

Using the value of

$cos30^{\circ}=\frac{\sqrt 3}{2}$

Height of triangular base of the pyramid,h=$9\sqrt{3}in$

Option b is true.

Answer 2

Answer:

It's the second option 9 √ 3 in

Step-by-step explanation:

just did it on edge