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mestny [16]
3 years ago
15

At a local election there were two propositions on the ballot, R and S. Twice as many voters voted "yes" for R as for S. If the

number who voted "yes" for R but "no" for S was 750 and the number who voted "yes" for S but "no" for R was 310, how many voted "yes" for both propositions?a. 122b. 127c. 130d. 135
Mathematics
1 answer:
Over [174]3 years ago
7 0

Answer:

c. 130

Step-by-step explanation:

Let call B the quantity of voters who voted yes for both propositions.

From the question we know that twice as many voters voted "yes" for R as for S, that can be written as the following equation:

R+B=2(S+B)

Where R is the number who voted "yes" for R but "no2 for S and S is the number who voted "yes" for S but "no" for R.

Replacing R by 750 and S by 310 and solving for B, we get:

750+B=2(310+B)

750+B=620+2B

2B-B=750-620

B=130

So, 130 voters voted yes for both propositions

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Answer:

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Step-by-step explanation:

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a)

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b)

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c)

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d)

3\frac{3}{6} +2\frac{4}{9}\\\\=\frac{22}{9}  +\frac{21}{6} \\\\Simplifying\ the\ expression:\\\\=\frac{132+189}{54} \\\\=\frac{321}{54}\\\\=5\frac{51 }{54}

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Step-by-step explanation:

80%  of  N   =   24            where N  is  the total number of students

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There are 10 marbles in a bag. Four are blue, 3 are black and 2 white and 1 red. If the marbles are not replaced once they are d
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Given that there are 10 marbles in a bag. 4 are blue, 3 are black, 2 are white and 1 is red.

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