Answer:
0.004 million Euro is the translation gain
Explanation:
The total cost of asset before depreciation of dollar = dollar 7.2 million * 0.7538 = 5.427 million Euro
1 dollar = 0.7538 Euros
Cost of asset in Euros after after depreciation of dollar = 7.2 * 10^6 * 0.7500 = 5.4 million Euro
Total liabilities before depreciation of dollar = dollar 8.2 million * 0.7538 = 6.181 million Euro
Total liabilities after depreciation of dollar = dollar 8.2 million * 0.7500 = 6.15 million Euro
The total loss in asset value = 5.427 million -5.40 million = 0.027 million Euro
The total profit in liabilities = 6.181 million -6.15 million = 0.031 million Euro
Net profit = 0.031 million -0.027 million = 0.004 million Euro
Answer:
D.
Explanation:
A brokers' call can be defined as the interest rate that banks charge on loans given to brokerage firms. It is also known as call loan rates. The brokers use this loan to fund their traders' margin account.
The statements correct about brokers' calls from the given options is D. The broker's calls are funds used by both individuals and broker from the bank. Individuals use this loan to buy stocks whereas brokers borrow with an agreement to repay immediately.
Therefore, option D is correct.
Answer:
The path around the normal purchasing channel is known as Maverick Spending.
Explanation:
The Maverick spending refers to expenses made from purchases outside the original contract, breaking the rules of previously established processes. In this example, one professor decided to disobey the original agreement and find another supplier, even though that would increase the expense greatly.
This is an actual problem for many different companies that are trying to eliminate by implementing different measures such as <em>spend analysis</em>, <em>a list of verified suppliers</em> or <em>purchasing control</em>.
Answer:
They should operate Mine 1 for 1 hour and Mine 2 for 3 hours to meet the contractual obligations and minimize cost.
Explanation:
The formulation of the linear programming is:
Objective function:
Restrictions:
- High-grade ore: 
- Medium-grade ore: 
- Low-grade ore: 
- No negative hours: 
We start graphing the restrictions in a M1-M2 plane.
In the figure attached, we have the feasible region, where all the restrictions are validated, and the four points of intersection of 2 restrictions.
In one of this four points lies the minimum cost.
Graphically, we can graph the cost function over this feasible region, with different cost levels. When the line cost intersects one of the four points with the lowest level of cost, this is the optimum combination.
(NOTE: it is best to start with a low guessing of the cost and going up until it reaches one point in the feasible region).
The solution is for the point (M1=1, M2=3), with a cost of C=$680.
The cost function graph is attached.
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