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yuradex [85]
3 years ago
7

*** PLEASE help im stuck

Mathematics
1 answer:
Mila [183]3 years ago
6 0

The sum of the interior angles of a polygon will add up to 180 degrees. Four sides give you two triangles and that's the least amount you need to have a polygon. Every additional side after 4 will get you another triangle. So now that you know the basic information lets explain how the formula makes sense. First lets add a 2 to the equation for how many triangles are required count as polygon.

#triangles = 2

Next you need to factor in how each side after 4 sides are an extra triangle and since you already put down 2 triangle which is equal to 4 sides you need to subtract the required amount of sides by additional sides of a polygon.

#triangles = 2 + ( s - 4 )

After that you just simplify that equation to...

#triangles = ( s - 2 )

Finally you need to factor in the the degrees and since every triangle's sum of interior angles add up to 180 degrees that is the number you have to multiply against.

sum of interior angles of a polygon = ( s - 2 ) x 180.

I now it's wordy and repeats a lot, but I think its a good enough explain of how to find the sum of the interior angles of any polygon :)

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The area of the regular hexagon is 169.74 ft2 what is the perimeter, rounded to the nearest tenth
Bess [88]

Answer:

Perimeter of given regular hexagon is <em>48.5 ft</em>.

Step-by-step explanation:

Let <em>ABCDEF</em> be the regular hexagon as shown in the attached figure.

<em>O</em> be the intersection point of the diagonals <em>EB</em>, <em>FC </em>and <em>AD</em>.

As per the property of regular hexagon, all the 6 triangles formed are equilateral triangles.

In other words,

\triangle EOD, \triangle DOC, \triangle BOC, \triangle AOB, \triangle AOF , \triangle FOE are equilateral \triangle s.

Area of an equilateral \triangle is defined as :

\dfrac{\sqrt{3}}{4} \times a^{2}

Where <em>a </em>is the side of \triangle.

Area of hexagon = 6 \times \dfrac{\sqrt{3}}{4}\times a^{2}

We are given that area of hexagon = 169.74 ft^{2}

Let <em>s </em>be the side of hexagon.

\Rightarrow 6 \times \dfrac{\sqrt{3}}{4}s^{2} = 169.74 ft^{2}\\\Rightarrow s = 8.08 ft

A regular Hexagon is made up of 6 equal sides, so

Perimeter of a regular hexagon = 6 \times side

Perimeter = 6 \times 8.08

\Rightarrow 48.5 ft

So, perimeter of given regular hexagon is 48.5 ft.

6 0
3 years ago
Please help me out here and let it be right
barxatty [35]

Answer:

C

Step-by-step explanation:

The ratio is given as \frac{12}{9} = \frac{4}{3} in simplest form

However, if we consider each group of 4 X's to 3 O's then the ratio is

\frac{4}{3} → C


3 0
3 years ago
Read 2 more answers
Coefficient of b in expansion of (3+b)^4
Margarita [4]
Are you sure you want ONLY the coefficient of b?  If you expand this, you will have b in 3 of 4 terms.

According to Pascal's Triangle, the coefficients of (a+b)^4 are as follows:

                             1
                        1    2    1
                   1      3    3     1
              1       4     6     4     1

So (a+b)^4 would be 1a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + b^4

Here, you want (3 + b)^4.  Here's what that looks like:

3^4 + 4[3^3*b] + 6[3^2*b^2] + 4[3*b^3] + 1[b^4]

Which coeff did you want?
4 0
3 years ago
Rewrite the rational exponent as a radical.
valina [46]
To answer the given : <span>5 to the 3 over 4 power, to the 2 over 3 power, we multiply the powers 3/4 and 2/3 equal to 2/4 or 1/2. This is the simplified power of the equation. Hence, the equation is simplified to 5 to the power of 1 over 2. or square root of 5. Answer is C.</span>
4 0
3 years ago
HELP PLS FOR BRAINLIEST!
igomit [66]

Answer:

Electric force = 8.20x10⁻⁸ N

Gravitational force = 3.61x10⁻⁴⁷ N

Step-by-step explanation:

1. The electric force can be found using the following equation:

F_{e} = \frac{Kq_{e}q_{p}}{d^{2}}

Where:

K: is the Coulomb's constant = 9x10⁹ N.m²/C²      

q_{p}: is the charge of the proton = 1.6x10⁻¹⁹ C

q_{e}: is the charge of the electron = -1.6x10⁻¹⁹ C

d: is the distance = 5.3x10⁻¹¹ m

Hence, the magnitude of the electric force is:

|F_{e}| = \frac{9\cdot 10^{9} N.m^{2}/C^{2}*(-1.6\cdot 10^{-19} C)*1.6 \cdot 10^{-19} C}{(5.3 \cdot 10^{-11} m)^{2}} = 8.20 \cdot 10^{-8} N                

2. The gravitational force can be calculated as follows:

F_{g} = \frac{Gm_{e}m_{p}}{d^{2}}

Where:

m_{e}: is the electron's mass = 9.1x10⁻³¹ kg

m_{p}: is the proton's mass = 1.67x10⁻²⁷ kg

G: is the gravitational constant = 6.67x10⁻¹¹ N.m²/kg²

Therefore, the gravitational force is:

F_{g} = \frac{6.67 \cdot 10^{-11} N.m^{2}/kg^{2}*9.1 \cdot 10^{-31} kg*1.67 \cdot 10^{-27} kg}{(5.3 \cdot 10^{-11} m)^{2}} = 3.61 \cdot 10^{-47} N

As we can see, the gravitational force is much less than the electric force.

I hope it helps you!                                                      

5 0
3 years ago
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