The answer would be 12.4 .
Answer:
Cov(X, Y) =0.029.
Step-by-step explanation:
Given that :
The noise in a particular voltage signal has a constant mean of 0.9 V. that is μ = 0.9V ............(1)
Also, the two noise instances sampled τ seconds apart have a bivariate normal distribution with covariance.
0.04e–jτj/10 ............(2)
Having X and Y denoting the noise at times 3 s and 8 s, respectively, the difference of time = 8-3 = 5seconds.
That is, they are 5 seconds apart,
τ = 5 seconds..............(3)
Thus,
Cov(X, Y), for τ = 5seconds = 0.04e-5/10
= 0.04e-0.5 = 0.04/√e
= 0.04/1.6487
= 0.0292
Thus, Cov(X, Y) =0.029.
So if 3% on 5year term and then it increased 1% it won't be 5 anymore it would go by 6 because it has increased by 1% and just add 1200 6 times.
Answer:
Tessa receives £60
Step-by-step explanation:
The ratio is 5:3 so 5+3=8 which is then what you use to divide 96
96/8=12
12x5(the 5 comes from the ratio for Tess) is 60 therefore she receives £60
