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Free_Kalibri [48]
2 years ago
14

A bag contains 5 blue marbles, 2 green marbles, and 3 yellow marbles. What is the probability of choosing one green marble and t

hen a yellow marble with replacement? 3/50 1/15 1/2 6/10
Mathematics
1 answer:
Vesna [10]2 years ago
4 0

Answer:

Step-by-step explanation:

Total number of marbles = 5 + 2 + 3 = 10

Probability of choosing 1 green marble = 2/10

Probability of choosing 1 yellow marble = 3/10

Notice (and this is important) that the denominator didn't change. Why?

Because you replaced the first marble into the bag. That word replacement is critical in a problem of this nature. There is the term non replacement which means that the second draw would have a denominator of 9.

So what is the probability of P(green then yellow)?

P(green then yellow) = 3/10 * 2/10 = 6/100

Answer: P(green then yellow) = 3/50 because 6 / 100 reduces.

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The function given is,

f(x)=3x-1

a) Domain

This is the set of all points over which a function is defined.

Therefore, the domain of the function is

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b) Solving for the value of a

To solve for the value of a, the value of y = 0 at x = a

Therefore,

\begin{gathered} f(x)=3x-1 \\ \text{where,} \\ f(x)=y=0 \\ x=a \end{gathered}

Solving for a

\begin{gathered} 0=3(a)-1 \\ 0=3a-1 \\  \end{gathered}

Collect like terms

\begin{gathered} 3a=0+1 \\ 3a=1 \end{gathered}

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Hence,

a=\frac{1}{3}

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Step-by-step explanation:

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