Answer:
How many drinks should be sold to get a maximal profit? 468
Sales of the first one = 345 cups
Sales of the second one = 123 cups
Step-by-step explanation:
maximize 1.2F + 0.7S
where:
F = first type of drink
S = second type of drink
constraints:
sugar ⇒ 3F + 10S ≤ 3000
juice ⇒ 9F + 4S ≤ 3600
coffee ⇒ 4F + 5S ≤ 2000
using solver the maximum profit is $500.10
and the optimal solution is 345F + 123S
Answer:
C. y = | x | – 13
Step-by-step explanation:
y = | x | – 13
Answer:
y = |x| -13
Step-by-step explanation:
recall for any function y = f(x), to translate the function vertically by any value "a", we simply have to add "a" to f(x).
If a is positive, then the graph is translated in the positive y-direction (i.e upwards), if a is negative, then the graph is translated in the negative y-direction (i.e downwards)
In our case , the graph is translated vertically by 13 units (i.e a = 13) and it is to be translated downwards (i.e negative)
hence we add a= -13 to the original function.
y = f(x) + (-13)
y = |x| + (-13)
y = |x| -13
Answer:
11
Step-by-step explanation:
2 times 6 is 12 minus 1 is 11
Answer:
Yes, we reject the auto maker's claim.
Step-by-step explanation:
H0 : μ ≥ 20
H1 : μ < 20
Sample mean, xbar = 18 ;
Sample size, n = 36
Standard deviation, s = 5
At α = 0.01
The test statistic :
(xbar - μ) ÷ s /sqrt(n)
(18 - 20) ÷ 5/sqrt(36)
-2 /0.8333333
= - 2.4
Pvalue from test statistic : Pvalue = 0.00819
Pvalue < α
0.00819 < 0.01
Hence, we reject the Null
Answer:
3x2-3x+9
Step-by-step explanation:
(h-k)(3)
(X2+1-(x-2))(3)
(x2+1-x+2)(3)
3x2+3-3x+6
3x2-3x+9
