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2 years ago

6

One sunflower if 63 inches tall. Another if 4 and 7/8 inches shorter. How tall tall is the second sunflower. I don't know how to

solve this

2 answers:

VikaD [51]2 years ago

6 0

Multiply the number to get your product

goblinko [34]2 years ago

3 0

62 8/8 - 4 7/8 = 58 1/8

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Is the inverse of a function always a function? explain your answer please

lys-0071 [83]

No, i don't think so

In a function, one value of x is only assigned to one value of y

It's okay if you can get the same y value from two x value, but that mean that inverse can't be a function.

y = x^2 is a function

but inverse y = +/- √x is not

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2 years ago

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3 years ago

In a garden, 2/3 of the flowers are roses. Of the roses in the garden, 5/12 are yellow and the rest are red. What fraction of th

emmainna [20.7K]

7/18 of the flowers are red roses

because 5/12 are yellow, the rest would be red. so 7/12. but total roses are only 2/3 of the whole garden.

tip: when you see "of" in a fraction problem, it means you can multiply them.

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2 years ago

Josie is making pizza dough. Complete the double number line by filling in the missing values

Softa [21]

Answer:

$n = \frac{4}{3}c$

$c:0\ \ \ \frac{3}{4}\ \ \ \frac{3}{2}\ \ \ \frac{9}{4}\ \ \ 3\ \ \ 3\frac{3}{4}\\n:0\ \ \ \ 1\ \ \ 2\ \ \ 3\ \ \ \ 4\ \ \ \ 5$

Step-by-step explanation:

Given

See attachment for complete question

Required

Complete the double number line

The given double number lines represent a linear function between cups of flour (c) and number of batched (n)

Pick any two pairs:

$(c_1,n_1) = (\frac{3}{4},1)$

$(c_2,n_2) = (3\frac{3}{4},5)$

First, calculate the rate of change (i.e. slope, m):

$m = \frac{n_2 - n_1}{c_2 - c_1}$

$m = \frac{5-1}{3\frac{3}{4} - \frac{3}{4}}$

$m = \frac{4}{3}$

So: the equation is:

$n = m(c - c_1) + n_1$

This gives:

$n = \frac{4}{3}(c - \frac{3}{4}) + 1$

$n = \frac{4}{3}c - 1 + 1$

$n = \frac{4}{3}c$

So, the above represents the relationship between n and c.

<u>To complete the table</u>

When $n = 2$

Substitute $n = 2$ in: $n = \frac{4}{3}c$

$2 = \frac{4}{3}c$

Make c the subject

$c = \frac{3*2}{4}$

$c = \frac{3}{2}$

When $n = 3$

Substitute $n = 3$ in: $n = \frac{4}{3}c$

$3 = \frac{4}{3} * c$

Make c the subject

$c = \frac{3*3}{4}$

$c = \frac{9}{4}$

When $c=3$

Substitute $c=3$ in: $n = \frac{4}{3}c$

$n = \frac{4}{3} * 3$

$n = 4$

So, the complete table is:

$c:0\ \ \ \frac{3}{4}\ \ \ \frac{3}{2}\ \ \ \frac{9}{4}\ \ \ 3\ \ \ 3\frac{3}{4}\\n:0\ \ \ \ 1\ \ \ 2\ \ \ 3\ \ \ \ 4\ \ \ \ 5$

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2 years ago

Please find the surface area of each figure to the nearest tenth? Please show the work too...

MrRa [10]

The first one is 31.875 and the second is 12 I don't know how to explain to get it. Sorry

7 0

2 years ago