THE PROBABILITY OF AN EVENT IS 0.34. WHAT IS THE PROBABILITY THAT IT WILL NOT OCCUR.

frutty [35]

1) add 7 to both sides and get -5....so -5 >x
2) add 7 to both sides.....so get b<-5
3) add 17 to both side...so get z>1

6 0

3 years ago

Read 2 more answers

Alyssa took a math test for 20 questions and she answered 16 questions correctly in order to get an a she needs to answer at lea

Elenna [48]

Answer:

She did not qualify the exam.

Step-by-step explanation:

Given data

Total no of question in a test = 20

No. of question answered correctly = 16

Percentage of question answered correctly

$(\frac{16}{20}) 100 = 80$

But in order to get in the exam the student must have to score at least 90 %. But she got only 80 % so she did not qualify the exam.

6 0

3 years ago

No links, No Wrong Answers, No Jokes, No Long Explanations.....

Harrizon [31]

Answer:

B (there is a negative correlation)

Step-by-step explanation:

the data set if you were put on a linear set, you be a negative and most of the points would fit through or around the slope. so it is a neagtive correlation

5 0

2 years ago

Read 2 more answers

BRAINLIEST ✨

inna [77]

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, or

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, or

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, or

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.Check: (2 + 2/3), (2 + 3*2/3), (2 + 6*2/3)

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.Check: (2 + 2/3), (2 + 3*2/3), (2 + 6*2/3)= 8/3, 4, 6

Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.Check: (2 + 2/3), (2 + 3*2/3), (2 + 6*2/3)= 8/3, 4, 6Common ratio: 4/(8/3) = 3/2 same as 6/4 = 3/2. Correct.

Step-by-step explanation:

Am I right? just commet if I'm wrong

then TANKYOU>^_^<!

7 0

2 years ago

Timothy is putting fertilizer on a field after planting some crops. The directions on the barrel state to use 0.75 quarts for ea

mote1985 [20]

Answer

Find out the how much fertilizer will Timothy need for two fields, one that is 22.5 acres and one that is 38.25 acres .

To proof

As given

Timothy is putting fertilizer on a field after planting some crops

The directions on the barrel state to use 0.75 quarts for each acre of land.

fertilizer will Timothy need for 22.5 acres = 22.5 × 0.75

= 16.875 quarts

fertilizer will Timothy need for 38.25 acres = 38.25×0.75

= 28.6875 quarts

total fetilizer Timothy need for two fields = 16.875 + 28.6875

= 45.5625

= 45.6 ( approx )quarts

Therefore the total fertilizer will Timothy need for two fields be 45.6 ( approx )quarts .

Hence proved

6 0

3 years ago

THE PROBABILITY OF AN EVENT IS 0.34. WHAT IS THE PROBABILITY THAT IT WILL NOT OCCUR.​

THE PROBABILITY OF AN EVENT IS 0.34. WHAT IS THE PROBABILITY THAT IT WILL NOT OCCUR.