Answer: The mode is: 3 . The range is: 6 .
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Explanation:
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It would be best to list this values in the data set given, from least to greatest:
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{ 3, 3, 3, 3, 4, 5, 5, 6, 9 } .
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The mode is the number that occurs most frequently in the data set, which is: "3".
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{The number, "3", occurs FOUR (4) times. The number, "4", occurs ONE (1) time. The number, "5", occurs TWO (2) times. The number, "6", occurs ONE (1) time. The number, "9", occurs ONE (1) time.}.
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The range is calculated from subtracting the LOWEST value in the data set FROM the HIGHEST value in the data set.
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The lowest values in the data set is: "3" .
The highest value in the data set is: "9" .
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To calculate the range: 9 <span>− 3 = 6 . The range is: "6".
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Answer: The mode is: 3 . The range is: 6 .
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Answer:
Therefore the concentration of salt in the incoming brine is 1.73 g/L.
Step-by-step explanation:
Here the amount of incoming and outgoing of water are equal. Then the amount of water in the tank remain same = 10 liters.
Let the concentration of salt be a gram/L
Let the amount salt in the tank at any time t be Q(t).
Incoming rate = (a g/L)×(1 L/min)
=a g/min
The concentration of salt in the tank at any time t is = 
g/L
Outgoing rate = 
Integrating both sides
[ where c arbitrary constant]
Initial condition when t= 20 , Q(t)= 15 gram
Therefore ,
.......(1)
In the starting time t=0 and Q(t)=0
Putting t=0 and Q(t)=0 in equation (1) we get
Therefore the concentration of salt in the incoming brine is 1.73 g/L
Answer:
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Step-by-step explanation:
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24q-8=11 (use distributive property)
24q= 11+8
24q = 20
q= 20/24
q= 0.8
The answer is opposites apex. I hope this helps
