1) (12p-3)(12p-3)
=144p^2-36p+36p+9
=144p^2+9 (-36+36=0 so it cancels out)
27y^3 -343 starts out with 27y^3, and 343 is the cube of 7. Thus, we know immediately that 27y3 -343 is the diffeence of two squares.
The appropriate rule is a^3 - b^3 = (a - b)(a^2 + ab + b^2).
Here, we have 27y3 -343 = (3y - 7)(9y^2 + 12y + 49)
Answer:
There is not another decimal equivalent to this but thre is fractions which your would be, 1/2 2/4
Answer:
2^5 or 32
Step-by-step explanation:
