2 years ago

-3xy-x²y²+1 is evaluated when x=-1 and y=-1 , then what is the exact value ?

Mathematics

2 answers:

fredd [130]2 years ago

5 0

Answer:

-3

Step-by-step explanation:

-3(-1)(-1)-(-1)^2(-1)^2+1

=-3

hopes this helps?!?!

Juliette [100K]2 years ago

3 0

Answer -2

Step-by-step explanation:

-3(-1)(-1)-(-1)^2(-1)^2+1

-3-1+1+1

-4+2

=-2

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-3xy-x²y²+1 is evaluated when x=-1 and y=-1 , then what is the exact value ?​

-3xy-x²y²+1 is evaluated when x=-1 and y=-1 , then what is the exact value ?