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ankoles [38]
3 years ago
5

-3xy-x²y²+1 is evaluated when x=-1 and y=-1 , then what is the exact value ?​

Mathematics
2 answers:
fredd [130]3 years ago
5 0

Answer:

-3

Step-by-step explanation:

-3(-1)(-1)-(-1)^2(-1)^2+1

=-3

hopes this helps?!?!

Juliette [100K]3 years ago
3 0

Answer -2

Step-by-step explanation:

-3(-1)(-1)-(-1)^2(-1)^2+1

-3-1+1+1

-4+2

=-2

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An equilateral triangle ΔLMQ (see picture to the right) is drawn in the interior of square LMNP so that side is common. Find m∠L
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I don’t see the picture if I see it I can help you tho
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Function: y = x^2+ 5x - 7 <br> Vertex:( <br> Solutions:( <br> and
tino4ka555 [31]

Answer:

Vertex: (-\frac{5}{2} , -\frac{53}{4})

Solutions: (0,-7), (1, -1), (2, 7)

I hope this helps!

8 0
3 years ago
BRAINLIESTTT ASAP! PLEASE HELP ME :)
lions [1.4K]
<h3>Answer: Choice C</h3>

Here's how the verification would look like

\frac{\sin^2x+\cos^2x}{\cos x} = \sec x

\frac{1}{\cos x} = \sec x using the identity here

\sec x =  \sec x

5 0
3 years ago
How do i find the area between the two curves
viktelen [127]
A=22/10

A=integral(a,b) [f(x)-g(x)]dx

Since the function is even (the function is mirrored over the y axis) we can evaluate the integral from 0 to 1 and then multiply our answer by 2 since we have the same area on each side of the y axis.

We get A=2*int.(0, 1)[(x^2)-(-2x^4)]dx

Now we can integrate by term.

2*[int.(0, 1)[x^2]dx+int(0, 1)[2x^4]dx]

Now factor out constants.

2*[int(0,1)[x^2]dx+2int(0,1)[x^4]dx]

Now integrate.

2*[(x^3/3)|(0,1) + 2*(x^5/5)|(0,1)]

Now solve.

2*[(1/3)+2*(1/5)]

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Hope you can decipher what I wrote!
4 0
4 years ago
The accompanying data represent the miles per gallon of a random sample of cars with a​ three-cylinder, 1.0 liter engine.a. Comp
Kobotan [32]

Answer:

1). Z score = 1.464733

Mean = 38.87917

Standard deviation = 3.609405

2). Quartiles:

Q1 = 37.025

Q2 = 38.450

Q3 = 40.800

3). IQR = 3.775

4).

CI (lower fence) = 37.4351

CI (upper fence) =  40.32323

5). There is outlier in the data set. Please see attached box plot for evidence.

Step-by-step explanation:

1). By Z score, we mean:

Z = \frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}}},

where:

x-bar ==> mean(g) = 38.87917

\mu = 37.80

standard deviation = 3.609405

sample size (n) = 24.

2). By quantile, we mean:

Q = L + (i*(n/4) - Cf)*c

Where L is the lower class limit of the quartile class

Cf is the cumulative frequency before the quartile class

c  is the class size.

3) . IQR = Q3 - Q1

4). CI = \mu \pm *Z_{\alpha/2} \frac{\sigma}{\sqrt{n}},

Where Z_{\alpha/2}  ==> 1.96

In order to replicate and obtain the result, please use the R code below:

g = c(31.5, 36.0, 37.8, 38.5, 40.1, 42.2,34.2, 36.2, 38.1, 38.7, 40.6, 42.5,34.7, 37.3, 38.2, 39.5,  

41.4, 43.4,35.6, 37.6, 38.4, 39.6, 41.7, 49.3)

boxplot(g)

Z = (mean(g) - 37.8)/(sd(g)/sqrt(length(g)))

mean(g)

quantile(g)

IQR(g)

CIl = mean(g) - 1.96*(sd(g)/sqrt(length(g)))

CIU = mean(g) + 1.96*(sd(g)/sqrt(length(g)))

4 0
3 years ago
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