Question

In the absence of air resistance two balls are thrown upward from the same launch point. Ball a rises to a maximum height above the launch point that is four times greater than that of ball b. The launch speed of ball a is _______ times greater than that of ball b.

Answer 1

Answer:

Va is two times greater than Vb

Explanation:

The maximum height reached by the balls are:

$Ymax = \frac{Vo^2}{2g}$

Since we are told that Ya = 4Yb:

$Ya = \frac{Va^2}{2g} = 4* Yb = 4 * \frac{Vb^2}{2g}$

Simplifying the equation:

$Va^2 = 4*Vb^2$

$Va = 2*Vb$