Answer:
Explanation:
ASSUMING your speed is constant
f₀ = f(v + vo)/(v + vs)
Δf = f approach - f depart
69.5 = (769(343 + vo)/(343 + 0)) - (769(343 - vo)/(343 + 0))
69.5 = 769(2vo/343)
vo = 15.5 m/s
Answer:
(a) ΔP=0.0245 kPa
(b) P=9.14 kPa
(c)ΔP=0.0245 kPa
Explanation:
(a) As it is perfect gas we can use
(P₁V₁)/T₁=(P₂V₂)/T₂
Since this constant volume so
P₁/T₁=P₂/T₂
T₂ is change in temperature
T₂=1.00+273.16
T₂=274.16 K

ΔP=6.71449-6.69
ΔP=0.0245 kPa
(b) As

(c) Same steps as in part (a)

ΔP=9.164-9.14
ΔP=0.0245kPa
I might be wrong but I'm pretty sure It's B
Answer:
a. 2.53 μJ b. It will move away
Explanation:
a. What is the electric potential energy between the particles?
The electric potential energy U = kq₁q₂/r where k = 9 × 10⁹ Nm²/C², q₁ = 4.1 nC = 4.1 × 10⁻⁹ C, q₂ = 2.4 nC = 2.4 × 10⁻⁹ C and r = distance between charges = 3.5 cm = 3.5 × 10⁻² m.
Substituting the values of the variables into U, we have
U = kq₁q₂/r²
U = 9 × 10⁹ Nm²/C² × 4.1 × 10⁻⁹ C × 2.4 × 10⁻⁹ C/3.5 × 10⁻² m
U = 88.56 × 10⁻⁹ Nm²/3.5 × 10⁻² m
U = 25.3 × 10⁻⁷ Nm
U = 2.53 × 10⁻⁶ Nm
U = 2.53 × 10⁻⁶ J
U = 2.53 μJ
b. And if the second particle is released will it move forward or away from the source charge.
It will move away from the source charge since they have the same sign of charge. Since, opposite charges repel.
Answer:
The wavelength of the light determines its characteristics. For example, short wavelengths are high energy gamma-rays and x-rays, long wavelengths are low energy radio waves. The whole range of wavelengths is called the electromagnetic spectrum.