Answer:
Distance, d = 778.05 m
Explanation:
Given that,
Force acting on the car, F = 981 N
Mass of the car, m = 1550 kg
Initial speed of the car, v = 25 mi/h = 11.17 m/s
We need to find the distance covered by car if the force continues to be applied to the car. Firstly, lets find the acceleration of the car:
Let d is the distance covered by car. Using second equation of motion as :
So, the car will cover a distance of 778.05 meters.
Answer:
Force,
Explanation:
There are two positive charges, 2 C and 5 C, separated by a distance of 20 cm in a vacuum. What is the value of the modulus of the electrostatic force between them?
We have,
Charge on object 1, q₁ = 2 C
Charge on object 2, q₂ = 5 C
Distance between charges, r = 20 cm = 0.02 m
The electric force between two charges is given by the formula as follows :
Plugging all the values we get :
So, the electric force between two charges is .
Answer: The answer is letter H
Answer:
1) Joule
2) kgm²/s²
3) 10%
Explanation:
Question 1)
Luminosity is defined as the total amount of energy released from an object in a unit amount of time.
This means Luminosity is the ratio of energy and time.
Unit of Energy is Joules and Unit of Time is seconds, so unit of Luminosity would be Joule per second or Watts.
So, from the given options, the unit which would be used in Luminosity calculations is Joule.
Question 2)
Work = Force x Distance
SI unit of Work is Joule
SI unit of Force is Newton or kgm/s²
SI unit of Distance is meter(m)
Unit of Work = Unit of Force x Unit of Distance
Joule = kgm/s² x m
Joule = kgm²/s²
This means, the correct description of joule in terms of SI base units is kgm²/s²
Question 3)
Value of gravitational constant from the experiment = Nm²/kg²
The accepted or actual value of the gravitational constant = Nm²/kg²
We need to calculate the percentage error. Percentage error is defined as:
Here, original value is the accepted value. Using the values in this formula, we get:
Thus, this means the percentage error in the calculation of gravitational constant was 10%.
Answer : The order of reaction is 2 (second order) and the rate law is,
Explanation :
As the expression of rate is,
where,
R = rate
k = rate constant
[AB] = concentration of AB
n = order of the reaction
First we have to calculate the rate for 0.200 mol/L 'AB' concentration with initial rate 0.00320 mol/L.s
.............(1)
Now we have to calculate the rate for 0.400 mol/L 'AB' concentration with initial rate 0.0128 mol/L.s
.............(2)
Now dividing the equation 1 by equation 2, we get the order of reaction.
By solving the term, we get the value of 'n'.
n = 2
Thus, the order of reaction = n = 2
The rate law will be,
So we conclude that,
For n = 0, the rate law will be zero order.
For n = 1, the rate law will be first order.
For n = 2, the rate law will be second order.
and so on.....
Hence, the order of reaction is 2 (second order) and the rate law is,