Part A) Find BC, the distance from Tower 2 to the plane, to the nearest foot.
in the triangle ACD
sin16=CD/(7600+BD)--------> CD=sin16*(7600+BD)---------> equation 1
in the triangle BCD
sin24=CD/BD-----------> CD=sin24*BD---------------> equation 2
equation 1=equation 2
sin16*(7600+BD)=sin24*BD-----> sin16*7600+sin16*BD=sin24*BD
sin24*BD-sin16*BD=sin16*7600----> BD=[sin16*7600]/[sin24-sin16]
BD=15979 ft
in the triangle BCD
cos24=BD/BC---------> BC=BD/cos24-------> 15979/cos24-------> 17491
BC=17491 ft
the answer part 1) BC is 17491 ft
Part 2) Find CD, the height of the plane from the ground, to the nearest foot.
CD=sin24*BD ( remember equation 2)
BD=15979 ft
CD=sin24*15979 -----------> CD=6499 ft
the answer part 2) CD is 6499 ft
Answer:
23.56
Step-by-step explanation:
2(
) + 2
rh
2( 
)+ 2(1.5)(1)
23.56
Answer:
The answer for this problem is
C) y = -x + 6
Step-by-step explanation:
I know this because I just did the test
Answer:
45%
Step-by-step explanation:
45 boxes are shaded
so percentage shaded is 45 out of the total which is 100
so 45 / 100 X 100
=45%
If one acre is $52, you would multiply 1240 by 52. Your land in total is worth $64,480.
