For this case we have that by definition, the equation of a line in the point-slope form is given by:
Where:
m: It is the slope of the line and 
is a point through which the line passes.
We have the following equation of the slope-intersection form:
Where the slope is 
By definition, if two lines are perpendicular then the product of their slopes is -1.
Thus, a perpendicular line will have a slope:
Thus, the equation will be of the form:
Finally we substitute the given point and we have:
Answer:
Option B
Answer:
x= 4
y= -5
Step-by-step explanation:
-2x+6y=-38 equation 1
3x-4y=32 equation 2
using equation 1 we have:
-2x+6y=-38
6y +38 = 2x
3y + 19 = x equation 3
using equation 3 in equation 2 we have:
3(3y + 19) - 4y = 32
9y + 57 -4y =32
5y = 32 -57
5y = -25
y= -25/5
y = -5
so we have:
3y + 19 = x
3(-5) +19 = x
x= 4
Answer:
x = -3/4, 1
Step-by-step explanation:
Factor left side of the equation.
(4x + 3)(x - 1) = 0
Set factors equal to 0.
4x + 3 = 0
4x = -3
x = -3/4
x - 1 = 0
x = 1
