Question

Find three consecutive odd integers such that the sum of the smallest number and middle number is 27 less than 3 times the largest number.

Answer 1

Answer:

17, 19, 21

Step-by-step explanation:

If we denote the smallest number as x, then the middle number will be x + 2 and the largest number will be x + 2 + 2.

The equation is:

x + (x + 2) = 3 * (x + 2 + 2) - 27

2x + 2 = 3x + 12 - 27

2x - 3x = 12 - 27 - 2

-x = -17

x = 17

The numbers are: 17, 19, 21

Let's check to be sure:

17 + 19 = 36

3 * 21 - 27 = 63 - 27 = 36