The <em>speed</em> intervals such that the mileage of the vehicle described is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h]
<h3>How to determine the range of speed associate to desired gas mileages</h3>
In this question we have a <em>quadratic</em> function of the <em>gas</em> mileage (g), in miles per gallon, in terms of the <em>vehicle</em> speed (v), in miles per hour. Based on the information given in the statement we must solve for v the following <em>quadratic</em> function:
g = 10 + 0.7 · v - 0.01 · v² (1)
An effective approach consists in using a <em>graphing</em> tool, in which a <em>horizontal</em> line (g = 20) is applied on the <em>maximum desired</em> mileage such that we can determine the <em>speed</em> intervals. The <em>speed</em> intervals such that the mileage of the vehicle is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h].
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19 percent.
15/80 = <span>18.75, rounded is 19.</span>
Answer:
120 miles
Step-by-step explanation:
we know that
The speed is equal to the distance divided by the time
Let
s------> the speed in mph
d-----> the distance in miles
t -----> the time in hours
s=d/t
solve for the distance
d=s*t
<em>It will take Adam four hours to drive to Disney Park</em>
s=x mph
t=4 h
substitute
d=4x -----> equation A
<em>It will take Adam 2.5 times less time if driving 45 mph faster</em>
so
s=(x+45) mph
t=4/2.5=1.6 h
substitute
d=1.6(x+45) -----> equation B
equate equation A and equation B
4x=1.6(x+45)
Solve for x
4x=1.6x+72
4x-1.6x=72
2.4x=72
x=30 mph
Find the distance d
d=4x -----> d=4(30)=120 miles