Find three consecutive odd integers such that the sum of the smallest number and middle number is 27 less than 3 times the large
st number.
1 answer:
Answer:
17, 19, 21
Step-by-step explanation:
If we denote the smallest number as x, then the middle number will be x + 2 and the largest number will be x + 2 + 2.
The equation is:
x + (x + 2) = 3 * (x + 2 + 2) - 27
2x + 2 = 3x + 12 - 27
2x - 3x = 12 - 27 - 2
-x = -17
x = 17
The numbers are: 17, 19, 21
Let's check to be sure:
17 + 19 = 36
3 * 21 - 27 = 63 - 27 = 36
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Answer:
75
Step-by-step explanation:
Q1=55 Q2=67 Q3=75
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