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3 years ago

What is the answer for (3n + 5)(3n+6)

Mathematics

2 answers:

Rzqust [24]3 years ago

6 0

Answer:

Step-by-step explanation:

I just did the math and got this answer!!

HOPE IT HELPS!!!!

:):):):)

statuscvo [17]3 years ago

5 0

Answer:

9n^2 + 33n + 30

Step-by-step explanation:

You're looking to multiply these two binomials together, and then to simplify the result, to obtain the product.

Have you used the "FOIL" method of multiplying binomials?

That's what we'll apply here.

F: first terms. The product of the first terms 3n and 3n is 9n^2.

O: outer terms. The product of the outer terms 3n and 6 is 18n.

I: inner terms: 15n

L: last terms: 30

Putting this all together, we get 9n^2 + 18n + 15n + 30, or

9n^2 + 33n + 30 (this is the desired answer, the product of (3n + 5) and (3n+6).

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Write the following decimal in expanded notation 56.78

Fudgin [204]

Answer:

its the same answer 56.78

Step-by-step explanation:

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3 years ago

Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. Th

Verizon [17]

Answer:

$(21.9-19.8) -1.966\sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 1.422$

$(21.9-19.8) -1.966 \sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 2.778$

And we are 95% confident that the true difference means are between $1.422 \leq \mu_1 -\mu_2 \leq 2.778$

Step-by-step explanation:

We know the following info:

$\bar X_1 = 21.9$ sample mean for group 1

$\bar X_2 = 19.8$ sample mean for group 2

$s_1 = 3.4$ sample standard deviation for group 1

$s_2 = 3.5$ sample standard deviation for group 2

$n_1 = 200$ sample size group 1

$n_2 = 200$ sample size group 2

We want to find a confidence interval for the difference of means and the correct formula to do this is:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}$

Now we just need to find the critical value. The confidence level is 0.95 then the significance is $1-0.95 =0.05$ and $\alpha/2 =0.025$ . The degrees of freedom are given by:

$df= n_1 +n_2 -2= 200+200-2= 398$

The critical value for this case would be : $t_{\alpha/2}=1.966$

And replacing into the confidence interval formula we got:

$(21.9-19.8) -1.966\sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 1.422$

$(21.9-19.8) -1.966 \sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 2.778$

And we are 95% confident that the true difference means are between $1.422 \leq \mu_1 -\mu_2 \leq 2.778$

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3 years ago

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True

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$3000

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3 years ago

A square plastic tarp has a perimeter of 68 meters. How long is each side of the tarp?

alina1380 [7]

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2 years ago

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Have a nice Day , I would appreciate it if you could mark my answer brainliest

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3 years ago

What is the answer for (3n + 5)(3n+6)​

What is the answer for (3n + 5)(3n+6)